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mr_godi [17]
3 years ago
9

3(x-7)

- 7" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
castortr0y [4]3 years ago
5 0

Answer:

3x-21

Step-by-step explanation:

We want to distribute the 3

3(x-7)

3*x -3*7

3x-21

xxTIMURxx [149]3 years ago
5 0

<u><em>Hi there!</em></u>

<u><em>Answer:</em></u>

<u><em>3x-21</em></u>

Step-by-step explanation:

Distributive property: a(b+c)=ab+ac

A=3, B=x, C=7

First, you expand.

3x-3*7

3*x=3x

3*7=21

<u><em>3x-21</em></u>

<u><em>Final answer is 3x-21</em></u>

Hope this helps!

Have a nice day! :)

:D

-Charlie

Thank you! :)

:D


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5 0
3 years ago
for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation
Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~  t_n_-_1

where, \bar X = sample proportion of defective items = 12,898

             s = sample standard deviation = 7,719

            n = sample size = 5

             \mu = population mean

<em> Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation. </em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ; </u>

P(-2.776 < t_4 < 2.776) = 0.95  {As the critical value of t at 4 degrees of

                                               freedom are -2.776 & 2.776 with P = 2.5%}  

P(-2.776 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.776) = 0.95

P( -2.776 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.776 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.776 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.776 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.776 \times {\frac{s}{\sqrt{n} } } , \bar X+2.776 \times {\frac{s}{\sqrt{n} } } ]

                                = [ 12,898-2.776 \times {\frac{7,719}{\sqrt{5} } } , 12,898+2.776 \times {\frac{7,719}{\sqrt{5} } } ]

                               = [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

5 0
4 years ago
How did you get 95/12, there is no way
Llana [10]

Answer:

uhhh- well- whats the question?

Step-by-step explanation:

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Step-by-step explanation:

y-y1=m(x1-x2)

y-1=7(x-0)

y-1=7(x)

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