Answer:
Step-by-step explanation:
Multiplying Equation A by (1/3) and adding the result to Equation B will do the trick. Let's actually solve the problem!
Equation A: (5/3)x + 3y = 12
Equation B: 4x - 3y = 8
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(5/3 + 12/3)x = 15 Note how this has eliminated the variable
(17/3)x = 15 y.
x = (3/17)(15)
Answer:
1
Step-by-step explanation:
when multiplying fractions it doesn’t matter if they have the same denominator (bottom) just multiply straight across
(6/12)x(6/3)
36/36
1
Answer:
174
Step-by-step explanation:
thanks for the help guys
Answer:
Two times at (-1,0) and (2.5,0)
Step-by-step explanation:
When the graph intersects or touches x-axis, y is equal to 0
so y = -2x^2 + 3x + 5
=> 0 = -2x^2 + 3x + 5
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
so a = -2
b = 3
c = 5
substitute in the formula
x = [-3 +/- √(3^2 - 4x-2x5)]/2(-2)
x = [-3 +/- √(9 + 40)]/(-4)
x = [-3 +/- 7]/(-4)
x1 = (-3 + 7)/(-4) = 4/-4 = -1
x2 = (-3 - 7)/(-4) = -10/-4 = 5/2 = 2.5
so the graph has two x-intercepts (-1,0) and (2.5,0), therefore it intersects x-axis two times
