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2 years ago

Ethan went bowling on Saturday night. His scores were 128, 97, 123, and 108. What was his average score for the night?

Mathematics

1 answer:

telo118 [61]2 years ago

3 0

Answer:

$114$

Step-by-step explanation:

$97+108+123+128=456$

$\frac{456}{4} = 114$

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There are 9 cookies on each plate, and there are 12 cookies in the cookie jar. Complete the table to show the total number of co

kipiarov [429]

P C
3 39
4 48
5 57
6 66

9(3)=27+12=39=c

9(4)=36+12=48=c

57=9p+12
-12 -12
45=9p
divide by 9 both sides 45/9=5=p

c=9(6)+12
c=54+12
c=66

8 0

3 years ago

Work out the size of angle A.<br>11 cm<br>9 cm<br>38°

Nutka1998 [239]

Answer:

38° because the other two are cm? also you haven't linked a photo so I can't work out angle A

4 0

3 years ago

Find the value of annuity if the periodic deposit is $1500 at 8% compounded semiannually for 22 years

Jet001 [13]

Answer:

The value of annuity is $P_v = \$ 32058$

Step-by-step explanation:

From the question we are told that

The periodic payment is $P = \$ 1500$

The interest rate is $r = 8\% = 0.08$

Frequency at which it occurs in a year is n = 2 (semi-annually )

The number of years is $t = 22 \ years$

The value of the annuity is mathematically represented as

$P_v = P * [1 - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ]$ (reference EDUCBA website)

substituting values

$P_v = 1500 * [1 - (1 + \frac{0.08}{2} )^{-22 * 2} ] * [\frac{(1 + \frac{0.08}{2} )}{ \frac{0.08}{2} } ]$

$P_v = 1500 * [1 - (1.04 )^{-44} ] * [\frac{(1.04 )}{0.04} ]$

$P_v = 1500 * [1 - 0.178 ] * [\frac{(1.04 )}{0.04} ]$

$P_v = \$ 32058$

8 0

3 years ago

43 grams of copper and 7grams other metals in a birdhouse, 83 grams of copper and 17 grams of other metals. Which one has more c

andrew-mc [135]

Answer: cage I

Step-by-step explanation:

Given

43 gm of copper and 7 gram of other metal

Another cage has 83 gram of copper and 17 gm of other metals

Here, the percentage of copper is

For the first case

$\Rightarrow \dfrac{43}{43+7}\times 100=86\%$

For the second case

$\Rightarrow \dfrac{83}{83+17}\times 100=83\%$

So, the cage-I has more percentage of copper

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3 years ago

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5 0

3 years ago