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3 years ago

Write a polynomial function in standard form with the given zeros. x= 1,1,2

1 answer:

5 0

First we write factor form than we transform it into polynomial:
(x-1)(x-1)(x-2) = (x^2-2x+1)(x-2)

we multiplied first 2 factors. now we only need to multiply remaining factors and than to sum like terms

x^3 -2x^2+x-2x^2+4x-2 = x^3 - 4x^2 + 5x -2

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6х + 7 = 4х + 13 Solve for X

N76 [4]

Answer:

x = 3

Step-by-step explanation:

subtract 7 from both sides, then subtract 4x from both sides after

6x +7 = 4x + 13

-7 -7

6x = 4x +6

-4x -4x

2x = 6

divide both sides by 2x

answer x =3

7 0

3 years ago

Read 2 more answers

HELPPPPPPPPP ASAPPPPPPPP PLSSSS

yanalaym [24]

-1/3(px-2) = 9

ok! so first we want to isolate x.

multiply both sides by -3/1 (this is the reciprocal of -1/3)

(px-2) = -27

px = -27 + 2

px = -25

x = -25/p

hope this helped!

8 0

3 years ago

Fancy goldfish x cost $3 each and common goldfish y cost $1 each.Graph the function y=20-3x to determine how many of each type o

aniked [119]

The pairs of goldfish Tasha can buy for $20 are $(0,20), (1,17), (2,14),$

$(3,11),(4,8),(5,5),and (6,2)$

Step-by-step explanation:

To find the how many type of goldfish that Tasha can buy for $20 is the set of positive ordered pairs.

Let x denote the number of fancy goldfish.

Let y denote the number of common goldfish.

To find how much goldfish can Tasha buy for $20 is to substitute the value for x in the equation $y=20-3x$

Now, substituting $x=0$ in $y=20-3x$ , we get,

$y=20$

The ordered pair is $(0,20)$

Similarly, substituting $x=1$ ,

$y=20-3(1)\\y=20-3\\y=17$

For $x=2$ ,

$y=20-6\\y=14$

For $x=3$ ,

$y=20-9\\y=11$

For $x=4$ ,

$y=20-12\\y=8$

For $x=5$ ,

$y=20-15\\y=15$

For $x=6$ ,

$y=20-18\\y=2$

Thus, the pairs of goldfish Tasha can buy for $20 are $(0,20), (1,17), (2,14),$ $(3,11),(4,8),(5,5),and (6,2)$

4 0

3 years ago

What is the simplified base of the function f(x)=1/4(<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B108%7D%20%5E%7Bx%5C%5C%7

JulsSmile [24]

The simplified function of $f(x) = \frac 14(\sqrt[3]{108^x})$ is $f(x) = \frac {3^x}4(\sqrt[3]{4})^x$

<h3>How to simplify the base function?</h3>

The function is given as:

$f(x) = \frac 14(\sqrt[3]{108^x})$

Expand 108

$f(x) = \frac 14(\sqrt[3]{27 * 4})^x$

Take the cube root of 27

$f(x) = \frac 14 * 3^x(\sqrt[3]{4})^x$

Evaluate the product

$f(x) = \frac {3^x}4(\sqrt[3]{4})^x$

Hence, the simplified function of $f(x) = \frac 14(\sqrt[3]{108^x})$ is $f(x) = \frac {3^x}4(\sqrt[3]{4})^x$