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2 years ago

43. What four segments are perpendicular to plane JKPN?

Mathematics

1 answer:

Len [333]2 years ago

4 0

Answer:

Step-by-step explanation:

Remember, the question ask for perpendicular segments, not perpendicular planes. Any segment that intersect with plane JKPN and create 90˚ angles are perpendicular.

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Dimas [21]

Answer:

0.150 < (Proportion of Sandy's pie) < 0.167

15% < (Percentage of Sandy's pie) < 16.7%

Step-by-step explanation:

Total percentage of pie = 100% or 1

George, Sandy, Carlos, and Michelle all ate a piece of the pie.

George ate a fraction of 0.150

Michelle ate a fraction of (1/6) = 0.167

Carlos ate a fraction of (1/7) = 0.143

The amount of pie left = 1 - 0.15 - (1/6) - (1/7) = 0.5405

And Sandy is known to eat more than two of her friends, but less than one of them.

Of the amount of pie eaten by the first 3 friends, (1/6) is the highest proportion.

Hence, it is evident that Sandy ate more than 0.143 and 0.150 (Carlos and George) but less than Michelle (0.167).

So, mathematically, the possible proportion of cake that Sandy ate is

0.150 < (Proportion of Sandy's pie) < 0.167

Hope this Helps!!!

7 0

3 years ago

Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x

Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

r ² - 3r + 2 = (r - 2) (r - 1) = 0

with roots r = 2 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(2x) + C₂ exp(x)

For the ansatz particular solution, we might first try

y (part.) = (ax + b) + (cx + d) exp(x) + e exp(3x)

where ax + b corresponds to the 2x term on the right side, (cx + d) exp(x) corresponds to (1 + 2x) exp(x), and e exp(3x) corresponds to 4 exp(3x).

However, exp(x) is already accounted for in the characteristic solution, we multiply the second group by x :

y (part.) = (ax + b) + (cx ² + dx) exp(x) + e exp(3x)

Now take the derivatives of y (part.), substitute them into the DE, and solve for the coefficients.

y' (part.) = a + (2cx + d) exp(x) + (cx ² + dx) exp(x) + 3e exp(3x)

… = a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)

y'' (part.) = (2cx + 2c + d) exp(x) + (cx ² + (2c + d)x + d) exp(x) + 9e exp(3x)

… = (cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

Substituting every relevant expression and simplifying reduces the equation to

(cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

… - 3 [a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)]

… +2 [(ax + b) + (cx ² + dx) exp(x) + e exp(3x)]

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

… … …

2ax - 3a + 2b + (-2cx + 2c - d) exp(x) + 2e exp(3x)

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

x : 2a = 2

1 : -3a + 2b = 0

exp(x) : 2c - d = 1

x exp(x) : -2c = 2

exp(3x) : 2e = 4

Solving the system gives

a = 1, b = 3/2, c = -1, d = -3, e = 2

Then the general solution to the DE is

y(x) = C₁ exp(2x) + C₂ exp(x) + x + 3/2 - (x ² + 3x) exp(x) + 2 exp(3x)

4 0

3 years ago

Rectangle 1 has length 10 and width 20. Rectangle 2 is made by multiplying each dimension of Rectangle 1 by a factor of k=3

Gwar [14]

Answer:

30cm, 60cm

Step-by-step explanation:

Given data

Dimensions of the first rectangle

Length =10cm

Width =20cm

We are told that the dimensions of the second rectangle is gotten by multiplying the first rectangle by 3

Hence the dimensions of the second rectangle is

Length =10*3= 30cm

Width = 20*3= 60cm

5 0

3 years ago

Which of the following equations is a constant function? x = 5 y = x y = 5

GalinKa [24]

Answer:

Y=X

Step-by-step explanation:

5 0

3 years ago

In △ABC, AB=9.2 ft, BC=11.9 ft, and m∠B=27°.

Rashid [163]

Area of triangle = 1/2 ab sin c
Area of triangle = 1/2 (9.2)(11.9) sin (27)
Area of triangle = 24.85 ft²

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Answer: Area - 24.85 ft²
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3 0

4 years ago