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natulia [17]
3 years ago
11

Help me please ............​

Mathematics
1 answer:
worty [1.4K]3 years ago
8 0

Answer:

probably inverse.... less cooks means more hours

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Write an equation that defines me) as a trinomial where m(x)=(3x-1)(3-x)+4x^2+19
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6 0
3 years ago
What is the area of a semicircle whose perimeter is 72cm
Nuetrik [128]

Answer:

A = 307.9 sq/cm

Step-by-step explanation:

Find the radius of the semi-circle

diameter + half the circumference = 72 cm

2r + pi*r = 72

r(2+pi) = 72

 

r = 72%2F%28%282%2Bpi%29%29

r = 14

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what will be the area of that semicircle?

A =1%2F2*pi%2A14%5E2

A = 307.9 sq/cm

7 0
4 years ago
The image of the point (-6, -2)under a translation is (−7,0). Find the coordinates of the image of the point (7,0) under the sam
lesya692 [45]

Answer:

hello :  solutio  ( 6 ; 2)

Step-by-step explanation:

the translation is :    x' = x + a ....(*)

                                 y' = y + b ...(**)

calculate  the coordinates ( a ; b)  of vectro by the translation

you have : x' = -7    y' = 0     x = -6    y = -2

Substitute in (*) , (***) :   -7 = -6 +a

                                      0 = - 2 + b

a = -1   and b= 2

so :  x' = x - 1

      y' = y + 2

calculate now the coordinates of the image of the point (7,0) under the same translation.

x = 7  and b = 0

so : x' = 7-1 = 6   and y' = 0 + 2 = 2

the image is  : ( 6 ; 2 )

4 0
4 years ago
Need help pls<br>thank you in advance ​
ira [324]

Answer:

<h3><u>Mean</u></h3>

<u />

\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}

\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10

\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10

<h3><u>Standard Deviation</u></h3>

\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's.  Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

5 0
2 years ago
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