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dedylja [7]
3 years ago
8

Will somebody please help me​

Mathematics
2 answers:
lana66690 [7]3 years ago
6 0
I’m pretty sure that last one is write
PolarNik [594]3 years ago
5 0

Answer:

-9n-3

Step-by-step explanation:

(-7n)-2n=-9n

2+(-1)=-3

So, the question equals -9n-3 :)

You might be interested in
Evaluate <br><br> 14y ÷ 5 - 4.9 for y = 6
Lubov Fominskaja [6]

Answer:

The final answer is 11.9

Step-by-step explanation:

14 x 6 = 84

84/5 = 16.8

16.8 - 4.9 = 11.9

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

8 0
3 years ago
What is the area of the figure?
Kipish [7]

Answer:

17.98 square meters

Step-by-step explanation:

find the area of rectangle

length x width

6.2x1.8= 11.16

find area of triangle

base x height x 1/2

base= 6.2

height= 4-1.8= 2.2

area=2.2 x 6.2 x 1/2 = 6.82

add both together to get area of figure

6.82 + 11.16 = 17.98

5 0
3 years ago
How to estimate the square root of 32
ELEN [110]

Answer:

~6.5

Step-by-step explanation:

6*6=32 7*7=49 between 6 and 7 and the middle is 6.5

5 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST
cestrela7 [59]
Yea I wanna say you have the right answer
8 0
3 years ago
A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)
Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}

5 0
3 years ago
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