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dedylja [7]
3 years ago
8

Will somebody please help me​

Mathematics
2 answers:
lana66690 [7]3 years ago
6 0
I’m pretty sure that last one is write
PolarNik [594]3 years ago
5 0

Answer:

-9n-3

Step-by-step explanation:

(-7n)-2n=-9n

2+(-1)=-3

So, the question equals -9n-3 :)

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What’s the answer? (Due today by 7pm) Thanks!!
AnnZ [28]

Answer:

D.

90 x 1/2 = 45 km

The rate is 90 miles per hour and 30/60=1/2 so we multiply 1/2

Hope this helps

Step-by-step explanation:

5 0
3 years ago
The length of a rectangle picture frame is 2 centimeters more than twice it’s width. If the area of the frame is 364 square cent
sergeinik [125]

Answer:

Length:28 cm

Width: 13 cm

Step-by-step explanation:

Let

x ---> the length of a rectangle picture frame

y ---> the width of a rectangle picture frame

we know that

The area of a rectangle picture frame is equal to

A=xy

we have

A=364\ cm^2

so

364=xy ----> equation A

The length of a rectangle picture frame is 2 centimeters more than twice it’s width

so

x=2y+2 ---> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (28,13)

see the attached figure

therefore

Length:28 cm

Width: 13 cm

5 0
3 years ago
In rhombus ABCD, AB = 13 and AC = 25. Find the area of the rhombus to the nearest tenth.
const2013 [10]
Area=lengthxwidth
=25x13
=325
5 0
3 years ago
What is the missing leg length of the hypotenuse 23 and the other leg is 11??
valentinak56 [21]
To find the 3rd side of a triangle, use the pythagorean theorem.
a^2 + b^2 = c^2

a = 11
b = ?
c = 23

11^2 + b^2 = 23^2
121 + b^2 = 529
b^2 = 408
b = √408 = 2 √102 = 20.199, 20.2, or 20

The answer can be any of those.
6 0
3 years ago
Read 2 more answers
Triangle PQR has vertices at the following coordinates: P(0, 1), Q(3, 2), and R(5, -4). Determine whether or not triangle PQR is
vitfil [10]

Answer:

<h2>The triangle is not right triangle</h2>

Step-by-step explanation:

The steps in the above photo

I hope that is useful for you :)

7 0
3 years ago
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