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-Dominant- [34]
3 years ago
9

angle A and angle B are complementary that is their measurements add up to 90° Angle B measures 32° more than Angle A what are t

he measurements of the two angle
Mathematics
1 answer:
xenn [34]3 years ago
7 0
Angle A is 29 and Angle B is 61. It’s problem can be solved by written the equation X+X+32=90. This becomes 2X+32=90 subtract 32 from each side making 2X=58 divide by 2 X=29 and just plug x in to solve for both angle names.
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Kazeer [188]
I believe <span>angle 1 is 115° </span>
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3 years ago
Your latitude is 40.0 N. Which of the following would be the position of the NCP at this location?
MakcuM [25]

Answer:

The answer is b 50.0 N

Step-by-step explanation:

8 0
3 years ago
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide
FrozenT [24]

Question:

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$114.00. Assume the population standard deviation is ​$15.30. Construct a​ 90% confidence interval for the population mean.

Answer:

At the 90% confidence level, confidence interval = 110.2484 < μ < 117.7516

At the 95% confidence level, confidence interval = 109.53 < μ < 118.48

The 95% confidence interval is wider

Step-by-step explanation:

Here, we have

Sample size, n = 45

Sample mean, \bar x = $114.00

Population standard deviation, σ = $15.30

The formula for Confidence Interval, CI is given by the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Where, z is found for the 90% confidence level as ±1.645

Plugging in the values, we have;

CI=114\pm 1.645 \times \frac{15.3}{\sqrt{45}}

or CI: 110.2484 < μ < 117.7516

At 95% confidence level, we have our z value given as z = ±1.96

From which we have CI=114\pm 1.96 \times \frac{15.3}{\sqrt{45}}

Hence CI: 109.53 < μ < 118.48

To find the wider interval, we subtract their minimum from the maximum as follows;

90% Confidence level: 117.7516 - 110.2484 = 7.5

95% Confidence level: 118.47503 - 109.5297 = 8.94

Therefore, the 95% confidence interval is wider.

8 0
3 years ago
Read 2 more answers
Can u help me please ?
harina [27]
Check the attached file and let me know what you think.
Download docx
6 0
4 years ago
I really extremely need help! I will give you 5 stars and branilest
Ivanshal [37]

Answer:

37.5%

Step-by-step explanation:

12\32 = 6\16=3\8 =0.375

=37.5%

7 0
3 years ago
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