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2 years ago

HELP ME ASAP PWEASS

Mathematics

2 answers:

leva [86]2 years ago

5 0

Answer:

number 4

Step-by-step explanation:

the answer is Line segments M′N′ and O′P′ do not intersect and are closer together than MN and OP.

Nutka1998 [239]2 years ago

3 0

Answer:

number 2

Step-by-step explanation:

hoped that helped:P

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Which term best describes the angle below?

Masja [62]

Acute because it is less than 90 degrees

4 0

4 years ago

Read 2 more answers

If -y-2x^3=Y^2 then find D^2y/dx^2 at the point (-1,-2) in simplest form

algol13

Answer:

$\frac{d^2y}{dx^2} = \frac{-4}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-y - 2x³ = y²

Rate of change of tangent line at point (-1, -2)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Basic Power Rule]: $-y'-6x^2=2yy'$
[Algebra] Isolate y' terms: $-6x^2=2yy'+y'$
[Algebra] Factor y': $-6x^2=y'(2y+1)$
[Algebra] Isolate y': $\frac{-6x^2}{(2y+1)}=y'$
[Algebra] Rewrite: $y' = \frac{-6x^2}{(2y+1)}$

Step 3: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{-12x(2y+1)+6x^2(2y')}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x+12x^2y'}{(2y+1)^2}$
[Derivative] Back-Substitute y': $y'' = \frac{-24xy-12x+12x^2(\frac{-6x^2}{2y+1} )}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x-\frac{72x^4}{2y+1} }{(2y+1)^2}$

Step 4: Find Slope at Given Point

[Algebra] Substitute in x and y: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(-1)^4}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(1)}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Multiply: $y''(-1,-2) = \frac{-48+12-\frac{72}{-4+1} }{(-4+1)^2}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{(-3)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{9}$
[Pre-Algebra] Divide: $y''(-1,-2) = \frac{-36+24 }{9}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-12}{9}$
[Pre-Algebra] Simplify: $y''(-1,-2) = \frac{-4}{3}$

6 0

3 years ago

Henry can write 5 pages of his novel in 3 hours.

Readme [11.4K]

Cool
what is the questoin ? xD

5 0

3 years ago

A worker in a silver mine descends 70 feet. Use an integer to represent the change in the worker's position.

kherson [118]

Answer:

-70

Step-by-step explanation:

5 0

3 years ago

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The table shows the relationship between the number of minutes that a hose

Marina86 [1]

Answer:

(C)The relationship is multiplicative because the number of gallons can be

found by multiplying the number of minutes by 8.

Step-by-step explanation:

Given the table below which shows the relationship between the number of minutes that a hose has been on and the number of gallons of water that have been added to a plastic pool.

$\left|\begin{array}{c|c}$Minutes Hose On&$Gallons of Water in Pool\\-------&-------\\0&0\\5&40\\10&80\\15&120\\20&160\end{array}\right|$

We can see that if we multiply the first column by 8, we will obtain the second column. Therefore the relationship is multiplicative because the number of gallons can be found by multiplying the number of minutes by 8.

The correct option is C.

8 0

3 years ago