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3 years ago

The difference of two numbers is 3. Their sum is 13. Find the numbers.

Mathematics

1 answer:

den301095 [7]3 years ago

3 0

Answer:

5and 8 is the correct answer

hope it helps you have a good day

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Helpppp helppp helppp

worty [1.4K]

Answer:

a=2.4

b=13.9

c= -8.1

Step-by-step explanation:

a= 3-0.6= 2.4

b= 12.5-(-1.4)= 13.9

c= -5.2-2.9= -8.1

8 0

3 years ago

Leno4ka [110]

In reflection, translation and rotations the pre image and the image are congruent and in dilation they are similar <span />

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4 years ago

Simplify the expression 35e^9/5e^8

erastovalidia [21]

$\frac{35e {}^{9} }{5 {e}^{8} } \ \\ \\ \frac{7e {}^{9} }{e {}^{8} } \\ \\ \\ = 7e$

Step By Step Explanation:

Reduce: Reduce the fraction with 5
Simplify: Simplify the expression

Alternate Forms:

19.02797

<h3>☆彡Hanna</h3>

5 0

3 years ago

Which equals the product of (x – 3)(2x + 1)?

hram777 [196]

Answer:

2x^2 – 5x – 3

Step-by-step explanation:

<u>Apply FOIL method: </u>

=x*2x+x*1+(-3)*2x+(-3)*1

<u>Apply minus-plus rules:</u>

=2xx+1*x-3*2x-3*1

Simplify:

=2x^2 – 5x – 3

Your Answer Is 2x^2 – 5x – 3

plz mark me as brainliest :)

6 0

4 years ago

Read 2 more answers

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0

2 years ago