This is not possible. Why not? Because the smallest the variance can get is 0.
Recall that 's' represents the standard deviation, so s^2 is the variance. It basically measures how spread out the values are. The higher the variance, the more spread out the data. You can think of it as "average distance from the mean". If the variance is 0, then all of the values are at the same point. So you could have a list like {2,2,2,2,2} which has variance 0. We cannot get any smaller variance than that. If your teacher insists all the values in the list are different, then the variance will be greater than 0.
572 rounded to the nearest 10 is 570 and 572 rounded to nearest 100 is 600.
The slope f'(x) = [f(4) - f(2)]/(4-2)≥3,
so [f(4) - 13]/2 ≥3
f(4) -13 ≥ 6
f(4)≥19, so it can be as small as 19.
The denominator is 40
10-3=7 (number of students in the band who do not ride the bus)
7/40=0.175
0.174*100=17.5% chance
Hope this helps!
Answer:
b) It is a binomial with a degree of 3.
Step-by-step explanation:
We need to find about which is true about the polynomial –8m3 + 11m from the given choices.
There are two terms so it is binomial.
Highest exponent on variable m is 3 so degree is 3.
Correct matching choice is "It is a binomial with a degree of 3."
Hence final answer is choice "b) It is a binomial with a degree of 3."
