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Svetlanka [38]
2 years ago
12

What is the area of a regular hexagon inscribed in a circle of radius 8 meters?

Mathematics
1 answer:
MAXImum [283]2 years ago
4 0

Answer:

it's 166.277

Step-by-step explanation:

i took the test & got it right

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as a gift, you fill the calendar with packets of chocolate candy. Each packet has a volume of 2 cubic inches. Find the maximum n
qaws [65]
The picture of the calendar is shown in the attached image.

Now, first we will get the volume of the calendar itself, we can note the calendar has the shape of a triangular prism.
Volume of triangular prism = area of base * depth
The area of base = area of triangle = 1/2 * base * depth 
Therefore:
Volume of prism = 1/2 * base * height * depth
where:
base = 4 in
height is he height of the base = 6 in
depth is the depth of the calendar = 8 in
Therefore:
Volume of calendar = 1/2 * 4 * 6 * 8 = 96 in^3

Now, we are given that the volume of each candy is 2 in^3, this means that:
number of candies to fill the calendar = volume of calendar / volume of candy
                                                            = 96/2 
                                                            = 48 candies

Hope this helps :)

4 0
3 years ago
Simplify:0.3(x-2y)+0.5x-y
astraxan [27]

Answer:

0.3[x-2y] + 0.5x - y


Use the distributive property: a(b-c) = ab - ac


0.3x - 0.6y + 0.5x - y


Now, add/subtract all like terms


0.3x + 0.5x - 0.6y - y


0.8x - 1.6y


If you want, we can simplify that down further to:


0.8(x - 2y)



7 0
3 years ago
Read 2 more answers
What is the product?
ad-work [718]

Answer is C, just multiply and expand.

7 0
3 years ago
Read 2 more answers
542 increased by 1/4 of itself is?
Bas_tet [7]
542(1+1/4)

542(4/4+1/4)

542(5/4)

677.5


5 0
4 years ago
Read 2 more answers
Easy points for fun whats 9 times 9
sleet_krkn [62]

Answer:

81

Step-by-step explanation:

8 0
3 years ago
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