Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10

10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7

I'm assuming it's 57. Because 1/2 can equal .5 and 56.5+.5=57
B. 6
Explanation: 8(6+4)= 80
38+ 7(6)= 80
Answer:


Step-by-step explanation:
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