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2 years ago

8

What value of ‘W’ satisfies 8(w+4)=38+7w A. 8 B.6 C.11 D. 4.5

1 answer:

dlinn [17]2 years ago

5 0

B. 6

Explanation: 8(6+4)= 80
38+ 7(6)= 80

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A triangle has an area of 38.4 cm2. The

lisov135 [29]

Answer:

6cm

Step-by-step explanation:

$A = \frac{h_b b}{2}$

$38.4 = \frac{12.8_b b}{2}$

$b = 2\frac{A}{h_b}$

$b = 2\frac{38.4}{12.8}$ = 6

8 0

2 years ago

4 friends evenly divided up a n- slice pizza. One of the friends , Harris, ate 1 fewer slice than he received. How many slices o

LenKa [72]

4 friends evenly dividing up a n - slice pizza

So each one get $\frac{n}{4}$ slices of pizza.

For example, if n = 12 slice then each friend gets 12/4 = 3 pieces. If Harris ate one slice less then he ate $\frac{12}{4}-1$ =3 -1 = 2 pieces.

So the general expression for slices of pizza did Harris eat is

$\frac{n}{4}-1$

6 0

2 years ago

Read 2 more answers

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

a

$336.04 < \mu < 443.96$

b

The margin of error will increase

c

The margin of error will decreases

d

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

So

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

4 0

2 years ago

Which is the function rule that will transform a geometric figure by reflecting across the y-axis and

likoan [24]

I think it’s between the first and third one

8 0

1 year ago

A plant can manufacture 50 golf clubs per

Mazyrski [523]

Answer:

The correct equation is "y=30x+6147". A further explanation is given below.

Step-by-step explanation:

The given values are:

(x1, y1) = (50, 7647)

(x2, y2) = (100, 9147)

As we know,

The slope is,

⇒ $m=\frac{y2-y1}{x2-x1}$

On substituting the given values, we get

⇒ $=\frac{9147-7642}{100-50}$

⇒ $=\frac{1500}{50}$

⇒ $=30$

Now,

⇒ $(y-y1)=m(x-x1)$

On substituting the given values in the above equation, we get

⇒ $y-7647=30(x-50)$

⇒ $y-7647=30x-1500$

On adding "7647" both sides, we get

⇒ $y-7647+7647=30x-1500+7647$

⇒ $y=30x+6147$

3 0

1 year ago