Answer:
Kindly check explanation
Step-by-step explanation:
H0 : μ = 5500
H1 : μ > 5500
The test statistic assume normal distribution :
Test statistic :
(Xbar - μ) ÷ s/sqrt(n)
(5625.1 - 5500) ÷ 226.1/sqrt(15) = 2.1429 = 2.143
Pvalue from test statistic :
The Pvalue obtained using the calculator at df = 15 - 1 = 14 is 0.025083
α = 0.05
Since ;
Pvalue < α
0.025083 < 0.05 ; Reject H0
The confidence interval :
Xbar ± Tcritical * s/sqrt(n)
Tcritical at 95% = 1.761 ;
margin of error = 1.761 * 226.1/sqrt(15) = 102.805
Lower boundary : (5625.1 - 102.805) = 5522.295
(5522.295 ; ∞)
The hypothesized mean does not occur within the constructed confidence boundary. HENCE, there is significant eveidbce to support the claim that the true mean life of a biomedical device is greater than 5500
For 4) S.A = 224.37 cm
5) S.A = 192.74 in
Answer:
2x + 5y + 15
Step-by-step explanation:
Step 1: Combine like terms
2x + 2y + 3(y + 5)
Step 2: Distribute
2x + 2y + 3y + 15
Step 3: Combine like terms
2x + 5y + 15
Answer:
Below.
Step-by-step explanation:
(a). From the graph the x estimates of the turning points are
-1.8 and 1.1.
(b). The solutions are where the graph crosses the x axis .. They are:
x = -3, 0 and 2.
The answer is AAS congruency.
∠1 = ∠4
∠B = D
AC = AC (common)
∴ ΔADC ≅ ΔABC by AAS congruency.
Hope this helps :)
