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3 years ago

8

I need the answers please.

2 answers:

Brrunno [24]3 years ago

8 0

Answer:

$y=\frac{-5}{3}x+200\\$

Step-by-step explanation:

$slope=\frac{rise}{run}$

$\frac{-5}{3}$

y-int = 200

$y=\frac{-5}{3}x+200\\$

<em>good luck, i hope this helps :)</em>

Dmitriy789 [7]3 years ago

6 0

Answer:

y=3/8+.6

Step-by-step explanation:

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determine the radius of the cone ,if the voulime of the cone is 125 cm to the power of 3 and the height of the cone is 12cm. Rou

Salsk061 [2.6K]

For this case we have that by definition, the volume of a cone is given by:

$V = \frac {1} {3} * \pi * r ^ 2 * h$

Where:

r: It is the radius of the cone

h: It is the height of the cone

According to the statement data we have:

$h = 12 \ cm\\V = 125 \ cm ^ 3$

Substituting in the formula:

$125 = \frac {1} {3} * \pi * r ^ 2 * 12$

We cleared the radius:

$3 * 125 = \pi * r ^ 2 * 12\\\frac {3 * 125} {12 \pi} = r ^ 2\\9.9522 = r ^ 2\\r = \pm \sqrt {9.9522}$

We choose the positive value:

$r = 3.1547$

We round and we have that the radius of the cone is:

$r = 3.16 \ cm$

ANswer:

$r = 3.16 \ cm$

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3 years ago

A small boat can travel at 28 per hour how many hours will it take to go across the bay that is 56 miles wide

dsp73

Answer:

2 hours

Remember that time = distance/rate

The distance you need to cover is 56 miles, while you go 28 miles per hour. Using these, we get this:

time=56/28

time=2

So it will take two hours to go across a 56 mile wide bay at 28 mph.

Step-by-step explanation:

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3 years ago

What is 1 plus 1 divided by 10?

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Answer:

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Step-by-step explanation:

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3 years ago

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F(x)=x^2 horizontal shift of 3 vertical shift of -2 reflected over the x-axis. Write the equation

Cerrena [4.2K]

$f(x) = -(x-3)^{2} -2$ is the required function.

<u>Step-by-step explanation:</u>

We have to find the transformation after the horizontal and vertical shifts and then reflection over the x-axis for the given function.

$f(x) = x^{2}$

If there is a horizontal shift of 3, then the function becomes, $f(x) = (x-3)^{2}$

If there is a vertical shift of -2, then the function becomes, $f(x) = (x-3)^{2} -2$

The function is reflected over the x- axis then the function becomes,

$f(x) = -(x-3)^{2} -2$

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3 years ago

The portion of the parabola y²=4ax above the x-axis, where is form 0 to h is revolved about the x-axis. Show that the surface ar

castortr0y [4]

Answer:

See below for Part A.

Part B)

$\displaystyle h=\Big(\frac{125}{\pi}+27\Big)^\frac{2}{3}-9\approx7.4614$

Step-by-step explanation:

Part A)

The parabola given by the equation:

$y^2=4ax$

From 0 to <em>h</em> is revolved about the x-axis.

We can take the principal square root of both sides to acquire our function:

$y=f(x)=\sqrt{4ax}$

Please refer to the attachment below for the sketch.

The area of a surface of revolution is given by:

$\displaystyle S=2\pi\int_{a}^{b}r(x)\sqrt{1+\big[f^\prime(x)]^2} \,dx$

Where <em>r(x)</em> is the distance between <em>f</em> and the axis of revolution.

From the sketch, we can see that the distance between <em>f</em> and the AoR is simply our equation <em>y</em>. Hence:

$r(x)=y(x)=\sqrt{4ax}$

Now, we will need to find f’(x). We know that:

$f(x)=\sqrt{4ax}$

Then by the chain rule, f’(x) is:

$\displaystyle f^\prime(x)=\frac{1}{2\sqrt{4ax}}\cdot4a=\frac{2a}{\sqrt{4ax}}$

For our limits of integration, we are going from 0 to <em>h</em>.

Hence, our integral becomes:

$\displaystyle S=2\pi\int_{0}^{h}(\sqrt{4ax})\sqrt{1+\Big(\frac{2a}{\sqrt{4ax}}\Big)^2}\, dx$

Simplify:

$\displaystyle S=2\pi\int_{0}^{h}\sqrt{4ax}\Big(\sqrt{1+\frac{4a^2}{4ax}}\Big)\,dx$

Combine roots;

$\displaystyle S=2\pi\int_{0}^{h}\sqrt{4ax\Big(1+\frac{4a^2}{4ax}\Big)}\,dx$

Simplify:

$\displaystyle S=2\pi\int_{0}^{h}\sqrt{4ax+4a^2}\, dx$

Integrate. We can consider using u-substitution. We will let:

$u=4ax+4a^2\text{ then } du=4a\, dx$

We also need to change our limits of integration. So:

$u=4a(0)+4a^2=4a^2\text{ and } \\ u=4a(h)+4a^2=4ah+4a^2$

Hence, our new integral is:

$\displaystyle S=2\pi\int_{4a^2}^{4ah+4a^2}\sqrt{u}\, \Big(\frac{1}{4a}\Big)du$

Simplify and integrate:

$\displaystyle S=\frac{\pi}{2a}\Big[\,\frac{2}{3}u^{\frac{3}{2}}\Big|^{4ah+4a^2}_{4a^2}\Big]$

Simplify:

$\displaystyle S=\frac{\pi}{3a}\Big[\, u^\frac{3}{2}\Big|^{4ah+4a^2}_{4a^2}\Big]$

FTC:

$\displaystyle S=\frac{\pi}{3a}\Big[(4ah+4a^2)^\frac{3}{2}-(4a^2)^\frac{3}{2}\Big]$

Simplify each term. For the first term, we have:

$\displaystyle (4ah+4a^2)^\frac{3}{2}$

We can factor out the 4a:

$\displaystyle =(4a)^\frac{3}{2}(h+a)^\frac{3}{2}$

Simplify:

$\displaystyle =8a^\frac{3}{2}(h+a)^\frac{3}{2}$

For the second term, we have:

$\displaystyle (4a^2)^\frac{3}{2}$

Simplify:

$\displaystyle =(2a)^3$

Hence:

$\displaystyle =8a^3$

Thus, our equation becomes:

$\displaystyle S=\frac{\pi}{3a}\Big[8a^\frac{3}{2}(h+a)^\frac{3}{2}-8a^3\Big]$

We can factor out an 8a^(3/2). Hence:

$\displaystyle S=\frac{\pi}{3a}(8a^\frac{3}{2})\Big[(h+a)^\frac{3}{2}-a^\frac{3}{2}\Big]$

Simplify:

$\displaystyle S=\frac{8\pi}{3}\sqrt{a}\Big[(h+a)^\frac{3}{2}-a^\frac{3}{2}\Big]$

Hence, we have verified the surface area generated by the function.

Part B)

We have:

$y^2=36x$

We can rewrite this as:

$y^2=4(9)x$

Hence, a=9.

The surface area is 1000. So, S=1000.

Therefore, with our equation:

$\displaystyle S=\frac{8\pi}{3}\sqrt{a}\Big[(h+a)^\frac{3}{2}-a^\frac{3}{2}\Big]$

We can write:

$\displaystyle 1000=\frac{8\pi}{3}\sqrt{9}\Big[(h+9)^\frac{3}{2}-9^\frac{3}{2}\Big]$

Solve for h. Simplify:

$\displaystyle 1000=8\pi\Big[(h+9)^\frac{3}{2}-27\Big]$

Divide both sides by 8π:

$\displaystyle \frac{125}{\pi}=(h+9)^\frac{3}{2}-27$

Isolate term:

$\displaystyle \frac{125}{\pi}+27=(h+9)^\frac{3}{2}$

Raise both sides to 2/3:

$\displaystyle \Big(\frac{125}{\pi}+27\Big)^\frac{2}{3}=h+9$

Hence, the value of h is:

$\displaystyle h=\Big(\frac{125}{\pi}+27\Big)^\frac{2}{3}-9\approx7.4614$

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3 years ago

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