Complete Question:
The mean hourly wage for employees in goods-producing industries is currently $24.57 (Bureau of Labor Statistics website, April, 1 2, 201 2). Suppose we take a sample of employees from the manufacturing industry to see if the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries. State the null and alternative hypotheses we should use to test whether the population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the goods-producing industries
Answer:
Null hypothesis, H₀ : μ = 24.57
Alternative hypothesis,
: μ ≠ 24.57
Step-by-step explanation:
The mean hourly wage for the goods producing industry = $24.57
Since we want to see if the mean of hourly wage for the manufacturing industry is equal to $24.57( The mean f hourly wage for the good producing industry)
Therefore the, null hypothesis will be that there is no significant difference between the means of the hourly wages of both the goods producing and the manufacturing industries, while the alternative hypothesis will be that the means of their hourly wages are significantly different
Null hypothesis, H₀ : μ = 24.57
Alternative hypothesis,
: μ ≠ 24.57
Answer:
√193
Step-by-step explanation:
7^2 = 49
12^2 = 144
144 + 49= 193
√193 because you are trying to find c not c^2
Answer:
-6,-5,0,6,12
Step-by-step explanation:
The negative numbers are obviously smaller than the positive ones :)
Answer:
Due to the higher z-score, Norma should be offered the job
Step-by-step explanation:
Z-score:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
Whoever has the higher z-score should get the job.
Norma:
Norma got a score of 84.2; this version has a mean of 67.4 and a standard deviation of 14.
This means that 
So

Pierce:
Pierce got a score of 276.8; this version has a mean of 264 and a standard deviation of 16.
This means that 
So

Reyna:
Reyna got a score of 7.62; this version has a mean of 7.3 and a standard deviation of 0.8.
This means that 
So

Due to the higher z-score, Norma should be offered the job