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geniusboy [140]
3 years ago
13

Calculate the length

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0
I hope this helps you

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Anne has a broken ruler. It starts at the 3-inch mark and ends at the 12-inch mark. Explain how Anne could use the ruler to meas
Alexandra [31]
She would start at the 3 inch mark and count from there.
6 0
3 years ago
What is the domain and range of the set?<br> {(2,2.3),(5,2.3), (7,15)}
aleksandrvk [35]

Answer:

DOMAIN: 2, 5, 7

RANGE: 2.3, 2.3, 15

Step-by-step explanation:

Domain is always the first value of the set, and range is always the second value of the set.  Hope it makes sense, and that it helped.

Have a good day! goodluck.

3 0
3 years ago
Pls help with this someone i'm struggling with this!
AfilCa [17]

Answer:

x=9

Step-by-step explanation:

Remove the radical by raising each side to the index of the radical.

5 0
2 years ago
Read 2 more answers
1/3 + a + 5/4. what is A
USPshnik [31]

Answer:

a = -1.58

Step-by-step explanation:

1/3 +a+5/4 =0

1/3+5/4= -a

4+15/12 = -a

19/12 = -a

1.58= -a

1.58/-1 = -a/-1

-1.58 = a

6 0
3 years ago
Determine whether the following statements are true and give an explanation or a counter example. a. The Trapezoid Rule is exact
Norma-Jean [14]

Answer:

statement is TRUE  

statement is FALSE  

statement is TRUE  

Step-by-step explanation:

(a)  

By using the Trapezoidal Rule, the definite integral can be computed by applying linear interpolating formula on each sub interval, and then sum-up them, to get the value of the integral  

So, in computing a definite integral of a linear function, the approximated value occurred by using Trapezoidal Rule is same as the area of the region.  Thus, the value of the definite integral of a linear function is exact, by using the Trapezoidal Rule.  

Therefore, the statement is TRUE  

(b) Recollect that for each rule of both the midpoint and trapezoidal rules, the number of sub-internals, n increases by a factor of a. then the error decreases by a factor of a^2.  

So, for the midpoint rule, the number of sub-intervals, n is increased by a factor of 3, then the error is decreased by a factor of 32 = 9, not 8. Therefore, the statement is FALSE  

(c) Recollect that for each rule of both the midpoint and trapezoidal rules, the number of sub-internals, n increases by a factor of a. then the error decreases by a factor of a^2.  

So, for the trapezoidal rule, the number of sub-internals, n is increased by a factor of 4. then the error is decreased by a factor of 42 = 16  

Therefore, the statement is TRUE  

3 0
3 years ago
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