3) 4r⁻³ · 2r² = 4·2 r⁽⁻³⁺²⁾ = 8 r⁻¹ = 8/r
4) 8k⁵
7) 6xy²
Because there's an even number of values in this set, there is two middle values rather than one (31 and 34). To find the median we need to add them together and divide the sum by 2 (31 + 34 = 65, 65/2= 32.5) Our final answer is 32.5.
8 × 20= 160; 8 × 4= 32; 160 + 32= 192; 8 × t= 192; 192 ÷ 8= 24; t=24
The answer is t = 24
Hope this helps :)
Answer:
it is 1/2
Step-by-step explanation:
