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Natasha_Volkova [10]
2 years ago
12

The supermarket has 12 aisles. 9 of the aisles are empty. What percentage of the aisles are

Mathematics
2 answers:
kkurt [141]2 years ago
7 0

Answer:

75%

Step-by-step explanation:

To find percentage, divide the part by the whole.

part: 9 aisles

whole: 12 aisles

9/12= 0.75

multiply that decimal by 100

0.75 times 100 = 75

hope this helps!

mezya [45]2 years ago
3 0

Answer:

The awnser is 2/3 or 66.66%

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Substitute y = 15x to the equation y = 25 + 12.5x:

15x = 25 + 12.5x     <em>subtract 12.5x from both sides</em>

2.5x = 25    <em>divide both sides by 2.5</em>

x = 10

Substitute the value of x to the equation y = 15x:

y = (15)(10)

y = 150

<h3>Answer: x = 10 and y = 150</h3>
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Eddie used the incorrect ratio for sin

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This is my last ever question on brainly.com<br><br>please help
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  1. The distance between the means is equal to 8.
  2. The mean absolute deviation (MAD) for class A is equal to 2.
  3. The mean absolute deviation (MAD) for class B is equal to 2.
  4. Distance between the means = four (4) times the MAD.
  5. There is no overlap and the distance between the means of both classes A and B is between one (1) times the MAD and five (5) times the MAD.

<h3>What is a number line?</h3>

A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.

<h3>What is a line plot?</h3>

A line plot can be defined as a type of graph that is used to graphically represent a data set above a number line, while using crosses, dots, or any other mathematical symbol.

<h3>What is a mean?</h3>

In Mathematics, a mean is also referred to as an arithmetic average and it can be defined as a ratio of the sum of the total number in a data set (population) to the frequency of the data set.

Mathematically, the distance between the means of both classes A and B is given by:

Distance = Mean of class A - Mean of class B

Distance = 12 - 4

Distance = 8.

The mean absolute deviation (MAD) for class A is given by:

MAD A = 1/9[2(9 - 12) + (10 - 12) + (11 - 12) + (12 - 12) + (13 - 12) + (14 - 12) + 2(15 - 12)]

MAD A = 1/9[2(3) + (2) + (1) + 0 + (1) + (2) + (1) + 2(3)]

MAD A = 1/9[6 + 2 + 1 + 1 + 2 + 1 + 6]

MAD A = 1/9 × [18]

MAD A = 18/9

MAD A = 2.

Also, the mean absolute deviation (MAD) for class B is given by:

MAD B = 1/9[2(1 - 4) + (2 - 4) + (3 - 4) + (4 - 4) + (5 - 4) + (6 - 4) + 2(7 - 4)]

MAD B = 1/9[2(3) + 2(2) + (1) + (0) + (1) + (2) + 2(3)]

MAD B = 1/9[6 + 4 + 1 + 0 + 1 + 2 + 6]

MAD B = 1/9 × [18]

MAD B = 18/9

MAD B = 2.

Therefore, distance between the means = four (4) times the MAD.

Distance = Means × MAD

8 = 4 × 2.

In conclusion, we can infer and logically deduce that there is no overlap and the distance between the means of both classes A and B is between one (1) times the MAD and five (5) times the MAD.

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