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True [87]
3 years ago
13

Shelbi is drawing plans for a garden, measured in feet, which is shown on the coordinate plane.

Mathematics
2 answers:
fenix001 [56]3 years ago
7 0

Answer:32 square feet

Step-by-step explanation:

vaieri [72.5K]3 years ago
6 0

Answer:

32

Step-by-step explanation:

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17. Tonya's mother is 1.5 times as tall as
andrew-mc [135]

The question is incomplete:

17. Tonya's mother is 1.5 times as tall as  Tonya was when she was 6. How tall  is Tonya's mother? Use the correct  number of significant digits.

The image with the information about Tonya's height is attached.

Answer:

68 in.

Step-by-step explanation:

According to the information given, you can write the following expression:

x=1.5y

x=Tonya's mother height

y= Tony's height when she was 6

Also, you know from the table that Tonya's height when she was 6 was 45 in. and you can replace this value in the formula:

x=1.5*45

x=67.5

Because of this, the answer is that Tonya's mother height is 68 in.

3 0
3 years ago
You deposit $500 in an account that earns 4% simple annual interest entrance and each year is added to the principal to create a
ikadub [295]

Answer:

first year $20 second year $20.80 Third year $21.63

Step-by-step explanation: This is for an extra money per year so after the first year that is how much extra money he gets every year.

4 0
2 years ago
Shopping While shopping for clothes, Jaclyn spent $17 less than 2 times what Daniel spent. Jaclyn spent $11. Write and solve an
GalinKa [24]
X=14
Hope it helps!!!
6 0
3 years ago
Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
ivanzaharov [21]

Answer:

1508527.582 cm³/min

Step-by-step explanation:

The net rate of flow dV/dt = flow rate in - flow rate out

Let flow rate in = k. Since flow rate out = 6800 cm³/min,

dV/dt = k - 6800

Now, the volume of a cone V = πr²h/3 where r = radius of cone and h = height of cone

dV/dt = d(πr²h/3)/dt = (πr²dh/dt)/3 + 2πrhdr/dt (since dr/dt is not given we assume it is zero)

So, dV/dt = (πr²dh/dt)/3

Let h = height of tank = 12 m, r = radius of tank = diameter/2 = 3/2 = 1.5 m, h' = height when water level is rising at a rate of 21 cm/min = 3.5 m and r' = radius when water level is rising at a rate of 21 cm/min

Now, by similar triangles, h/r = h'/r'

r' = h'r/h = 3.5 m × 1.5 m/12 m = 5.25 m²/12 m = 2.625 m = 262.5 cm

Since the rate at which the water level is rising is dh/dt = 21 cm/min, and the radius at that point is r' = 262.5 cm.

The net rate of increase of water is dV/dt = (πr'²dh/dt)/3

dV/dt = (π(262.5 cm)² × 21 cm/min)/3

dV/dt = (π(68906.25 cm²) × 21 cm/min)/3

dV/dt = 1447031.25π/3 cm³

dV/dt = 4545982.745/3 cm³

dV/dt = 1515327.582 cm³/min

Since dV/dt = k - 6800 cm³/min

k = dV/dt - 6800 cm³/min

k = 1515327.582 cm³/min - 6800 cm³/min

k = 1508527.582 cm³/min

So, the rate at which water is pumped in is 1508527.582 cm³/min

5 0
3 years ago
I am sus lol so here is some points​
Masja [62]

Hello.

Have a beautiful and joyful day ahead

Thanks for points..

3 0
3 years ago
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