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2 years ago

Please help me thank you so much have a great day and also be nice to others and especially yourself

Mathematics

2 answers:

Illusion [34]2 years ago

7 0

Answer:

Step-by-step explanation:

Divide 80 by 10, and you will get 8.

When they ask you to fund the unit rate, it will typically be in some sort of measurement or price (pounds, inches, dollars, miles, etc.). They want you to find out how much one individual item would be, whether it's how much money, or how many inches, etc.

In this case, they want you to find the average amount of snow fallen in one day. Since it has been 10 days and 80 inches were dropped, you would divide the total amount of inches by the total amount of days in order to find how many inches were dropped in just one day.

ioda2 years ago

6 0

8 inches because 80/10=8

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After working 10 years as a bus driver, Izabel Antocicco was in an accident and became permanently disabled. She was 63 years ol

frozen [14]

Answer:

A. $2,506.50

Step-by-step explanation:

6 0

2 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

2 years ago

Determine the intercepts HELP PLEASE EMERGENCY

Ilya [14]

(-2,0) (0,6) (1,0) this should be it

3 0

2 years ago

The radius of a large sphere is 8 times the radius of a small sphere. the surface area of the large sphere is how many times the

kondaur [170]

Large sphere's radius = R,
small sphere's radius = r, R = 8r
surface area of a sphere (SA) = 4×pi×radius^2
So what we need is the SA of the larger in terms of the smaller sphere, so if:
SA (of R) = 4×pi×R^2, then plug in "8r" for "R"...
SA = 4×pi×(8r)^2 = 4×3.14×64r^2
SA = 12.57×64r^2 = 804 r^2
Therefore the SA of the larger sphere is 804 times the SA of the smaller sphere.
I hope that makes sense!

8 0

2 years ago

Please help me I need it bow

Tanzania [10]

Answer: A

Step-by-step explanation:

If the fraction is negative, and the numerator and denominator is negative, then if you were to do anything to them it would become a positive

6 0

2 years ago

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