A boy throws a baseball across a field. The ball reaches its maximum height, 18 meters, after 1 second. After approximately 2.3
seconds, the ball lands on the ground. The ball’s motion can be modeled using the function f(x) = –10x2 + 20x + 8. What is the height of the ball 1.5 seconds after it is thrown? A. 11.7 meters B. 13.8 meters C. 15.5 meters D. 17.5 meters
Since the ball will reach the maximum height of 18 meters after 1 second, meaning after 1 second it will start to go down. So will expect that the height will be lower than 18 m after 1.5 s. f(x) = –10x2 + 20x + 8 f(x) = –10(1.5^2) + 20(1.5) + 8 f(x) = 15.5 m
