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2 years ago

How can i use the slope formula to find the slope between (2, -7) and (1, 6)

Mathematics

2 answers:

olga nikolaevna [1]2 years ago

7 0

Answer:

To find the slope using the formula, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points.

- The slope formula is m=(y2-y1)/(x2-x1), or the change in the y values over the change in the x values.

<u><em>Tell me if you want the answer of what the slope is.</em></u> Although, it would be better for you to work it out yourself!

Hope that helps. x

meriva2 years ago

6 0

Answer:

-13

Step-by-step explanation:

gradient = change in y/change in x

change in y = 6- -7=13

change in x = 1-2 = -1

gradient = 13/-1 = -13

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X2-3xy-5xy-7y2+4x2+8y2

Zepler [3.9K]

For this case we must simplify the following expression:

$x ^ 2-3xy-5xy-7y ^ 2 + 4x ^ 2 + 8y ^ 2$

We must add similar terms taking into account that:

Equal signs are added and the same sign is placed.

Different signs are subtracted and the major sign is placed.

$(x ^ 2 + 4x ^ 2) + (- 3xy-5xy) + (- 7y ^ 2 + 8y ^ 2) =\\5x ^ 2-8xy + y ^ 2$

Thus, the simplified expression is:

$5x ^ 2-8xy + y ^ 2$

Answer:

$5x ^ 2-8xy + y ^ 2$

4 0

4 years ago

What is the area of this figure

konstantin123 [22]

Answer:

108

Step-by-step explanation:

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2 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

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Jet001 [13]

The answer would be mercury.

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3 years ago

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Alex787 [66]

Answer:

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