In the least-squares line y = 5 − 9x, what is the value of the slope?

2 answers:

6 0

Just convert to standard form using Ax + By = C = -(A/B) where A = -9 and B = 5.
m = -9/1 which translates to -9.
Our slope is -9.

maxonik [38]3 years ago

6 0

Answer:

Slope= -9

Step-by-step explanation:

Remember that functions in the form of the slope are represented like this:

Y=mx+c

The function that is given to us just moves C of place, and the m is the number that is located right aside of the variable x, so the slope is -9, this is how much would the graph will grow or decrease with the increase on the value of the variable x.

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Lana71 [14]

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HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

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What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

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And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$