Answer:
The total surface area of triangular pyramid is 172 cm squared
Step-by-step explanation:
Triangular pyramid:
- Number of faces 4.
- Number of vertices of a triangular pyramid is 6.
- The volume is
. A= area of the pyramid's base and H= height of the pyramid.
- The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.
Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.
The 3 sides of the triangular pyramid is triangle in shape.
The area of triangle is 
.
The lateral surface area of the triangular pyramid is
cm squared
=129 cm squared
The total surface area of triangular pyramid is
=Area of the base + lateral surface area
=(43+129) cm squared
=172 cm squared
8 flares are most likely to occur in one century. However, the answer is 8.33, so take that into account.
Answer:
x = 7.5
y = 14
m<1 = 87°
m<7 = 93°
Step-by-step explanation:
Given:
m<2 = (14x - 12),
m<6 = (5y + 23),
m<8 = (8x + 27)
m<2 + m<8 = 180° (consecutive exterior angles are supplementary)
(14x - 12) + (8x + 27) = 180 (substitution)
Solve for x
14x - 12 + 8x + 27 = 180
Collect like terms
22x + 15 = 180
Subtract 15 from each side
22x = 180 - 15
22x = 165
Divide both sides by 22
x = 7.5
m<2 = m<6 (corresponding angles are congruent)
(14x - 12) = (5y + 23) (substitution)
Plug in the value of x
14(7.5) - 12 = 5y + 23
105 - 12 = 5y + 23
93 = 5y + 23
Subtract 23 from each side
93 - 23 = 5y
70 = 5y
Divide both sides by 5
14 = y
y = 14
✅m<1 = m<8 (alternate exterior angles are congruent)
m<1 = (8x + 27) (substitution)
Plug in the value of x
m<1 = 8(7.5) + 27 = 87°
m<7 = m<2 (alternate exterior angles are congruent)
m<7 = (14x - 12) (substitution)
Plug in the value of x
m<7 = 14(7.5) - 12 = 93°
She would have 40% left for the sides. She took off 50% (25%+25%), then 50% of 80 is 40. Hope it helps.
Answer:
Sin 90°=1
Step-by-step explanation:
A unit circle is a circle with a radius of 1 .Because the radius is 1, it is possible to directly measure the sine, cosine and tangent.
<em>using the unit circle where 90° is the limit as the hypotenuse approaches the vertical y-axis which is positive.</em>
Sine=opposite/hypotenuse
Sin=O/H
<u>Applying the limits</u>
Sine 90°=1/1= 1
cos 90° =0/1 =0
or
When the angle formed at the origin of the unit circle in the 1st quadrant is 0°, cos 0°=1 sin0°=0 and tan 0°=0
When we increase the angle until it is 90°, cos 90°=0, sin 90°=1 and tan 90°=undefined
