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Answer:
P = 0.018
Step-by-step explanation:
In this problem, the null and alterantive hypothesis are:
If the sample has a size of n = 40, the degrees of freedom are 40-1 = 39.
If the value of the test statistic is t = 2.463, we can look up in a t-table to find the p-value. In this test, because the mean can be bigger than 73 or smaller than 73, we have to do a two-tailed test.
For a two-tailed test for t = 2.463 and df = 39, the P-value is P = 0.018.
Assuming the matrix is
we have characteristic polynomial given by the equation
we have characteristic polynomial given by the equation