Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
Answer:
I'm pretty sure 44cm2
Step-by-step explanation:
If im wrong sorry if Im right give me 5 stars pls
The colored one would be a 1 in 4 and the b&w is a 1 in 5 :1
The answer is: 1/ 3(3x+2)
y2 - y1 / x2 - x1 = slope
2 - -2 / 2 - -1
4/3
<u>the slope of the line is 4/3</u>
