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liraira [26]
2 years ago
6

Identify the percent increase in total sales and the percent increase in sales of trench coats. Then find which percent of incre

ase is greater and by how much greater it is than the other. (Round your answer to the nearest tenth. ) a. Sales of trench coats increased 0. 7 percentage points faster than total coat sales. B. Sales of trench coats increased 8. 3 percentage points faster than total coat sales. C. Total coat sales increased 2. 5 percentage points faster than sales of trench coats. D. Total coat sales increased 10. 7 percentage points faster than sales of trench coats.
Business
1 answer:
geniusboy [140]2 years ago
4 0

The percentage increase in the total sales for 2006 is 15% while the increase in sales of the trench coats is 23.3%; therefore the percentage increase in total sales of trench coats is 8.3% faster.

Computation:

1. The total amount of sales for 2006 and 2007:

\begin{aligned}\text{Sales of 2006}&=103+297+210+213+137\\&=960\end{aligned}

\begin{aligned}\text{Sales of 2007}&=127+223+210+285+259\\&=1104\end{aligned}

2. Now, the percentage increase will be determined for the total number of coats and trench coats:

For the total number of coats, the values used will be the total sales of 2006, and total sales of 2007.

\begin{aligned}\text{Percentage Increase}&=\dfrac{\text{Sales of 2007}-\text{Sales of 2006}}{\text{Sales of 2006}}\times100\\&=\dfrac{1104-960}{960}\times100\\&=15\%\end{aligned}

For the trench coats the values used will be the sale of trench coats in 2006 and 2007.

\begin{aligned}\text{Percentage Increase in Sale of Trench Coat}&=\dfrac{\text{Sales of 2007}-\text{Sales of 2006}}{\text{Sales of 2006}}\times100\\&=\dfrac{127-103}{103}\times100\\&=23.33\%\end{aligned}

3. Now, the  net percentage increase in sales due to the trench coats is computed as follows:

\begin{aligned}\text{Net Percentage Change}&=\text{\text{Percentage Increase in Trench Coat}-\text{Percentage Increase}}\\&=23.33\%-15\%\\&=8.3\%\end{aligned}

Therefore, the correct option is option B. Sales of trench coats increased 8. 3 percentage points faster than total coat sales.

To know more about percentages of increase in sales, refer to the link:

brainly.com/question/45525

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2. Depreciation expense $9,614

      To Accumulated Depreciation - Equipment  $9,614

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= ($53,420 - $5,350) ÷ ( 5 years)

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On January 1, Hurley Corporation issues $500,000, 5-year, 12% bonds at 96 with interest payable on January 1. The entry on Janua
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b. credit to Cash $60,000.

Explanation:

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Hurley Corporation issues the principal amount of $500,000

Time = 5 years

Rate = 12%  at 96  with interest payable on January 1

Discount on issue  =500000 × (1 - 0.96) = 20000

Annual discount  amortization= 20000/5 = 4000                  

Interest payable  = 500000× 12% =  60000

From the information given in the question; we can have a journal entry to determine the what the straight-line method will include.

So, let have a look at the table below:

Discount on issue                     20000                                      

Annual discount                        4000

amortization

                                                     Debit                            Credit

Interest expense                         64000

Discount on Bonds payable                                            4000

Interest payable                                                               60000

Now; The January 1 entries will now be as follows:

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Interest payable                           60,000

Cash                                                                                60,000

Thus; The entry on January 1 to record payment of bond interest assuming amortization of bond discount used the straight-line method will include a: <u>Credit to cash  $60,000</u>

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Answer:

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Explanation:

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  • let q = quarters
  • let d = dimes

first step:

d = 3 (n + q) = 3n + 3q

d + n + q = 284

0.10d + 0.05n + 0.25q = 27.25

second step:

3n + 3q + n + q = 284

0.10 (3n + 3q) + 0.5n + 0.25q = 27.25

third step:

4n + 4q = 284

0.3n + 0.3q + 0.05n + 0.25q = 27.25

fourth step:

n + q = 71

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fifth step:

replace q = 71 - n

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seventh step:

11.8 = 0.2n

eighth step:

n = 59

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d = 284 - n - q = 284 - 59 - 12 = 213

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