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hammer [34]
3 years ago
12

Need answer rn plss Use the graph to write a linear function that relates y to x.

Mathematics
1 answer:
denpristay [2]3 years ago
3 0

Answer:

y = 1/3x - 1

Step-by-step explanation:

Using coordinates (0,3) and (3,4)

then slope m = (y2-y1)/(x2-x1)

m = (4-3)/(3-0) = 1/3

then y = mx + b => y = 1/3x + b

Using coordinate (0,3)

y = 1/3x + b

0 = 1/3(3) + b

0 = 1 + b

b = -1

then y = 1/3x - 1

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When abcd is drawn to scale would the lines a and d and b and c be parallel or not?
Tasya [4]

Answer: YES!

<u>Step-by-step explanation:</u>

Assuming ABCD is a parallelogram, the opposite sides are parallel

AB║DC     and       AD║ BC

5 0
4 years ago
What times what equals -3 in decimal form?<br> PLZ help me
Shalnov [3]
___ x ___ = -3.0
Is this is what you're trying to say?
If it is, the answer is -1.5 x 2.
6 0
4 years ago
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Find the possible values of r in the inequality 5 &gt; r - 3.
ioda
The answer to this question is A
3 0
4 years ago
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To make enough chili for the chili cook-off, Lee needs 20 pounds of ground
miss Akunina [59]

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50 dollars

Step-by-step explanation:

5 0
3 years ago
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Solve the equation 2^(2x+1)+8=17×2^x.
myrzilka [38]
Oooh, looks fun

ok
erm
we might want to know some properties
(x^m)(x^n)=x^{m+n}
(a^b)^c=a^{bc}
if a^m=a^n where a=a, then assume m=n

2^{2x+1}=(2^{2x})(2^1)
so
(2^{2x})(2)+8=17(2^x)
(2^{2x})(2)+2^3=17(2^x)
(2^x)^2(2)+2^3=17(2^x)
minus 17*2^x both sides
(2^x)^2(2)+2^3-17(2^x)=0
use u subsitution, u=2ˣ
(u)^2(2)+2^3-17(u)=0
solve 2u^2+8-17u=0
or
2u^2-17u+8=0
ac method
2 times 8=16
what 2 number multiply to get -17 and add to get 16
-16 and -1
2u²-1u-16u+8=0
(2u²-1u)+(-16u+8)=0
u(2u-1)+(-8)(2u-1)=0
(u-8)(2u-1)+0
u-8=0
u=8

2u-1=0
2u=1
u=1/2

now
u=2ˣ

8=2ˣ
2^3=2^x
3=x

and
\frac{1}{2}=2^x
2^{-1}=2^x
-1=x

x=-1 and 3
neat problem
8 0
3 years ago
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