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Vikentia [17]
3 years ago
5

I need help simplifying this

Mathematics
1 answer:
faust18 [17]3 years ago
3 0

Answer:

n^2

Step-by-step explanation:

cancel the common factor between n^7 and n^2

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Please change the numbers to the best-estimated value within each division problem:
sammy [17]

Answer:

27.9 (rounded, actual answer 27.909090, repeating)

3.7 (rounded, actual answer 3.70174672489)

6.7 (rounded, actual answer 6.67408231368)

Step-by-step explanation:

Divide

3 0
4 years ago
Tayler has $320 to pay for dining room chairs. She expects to pay about $80 per chair. Her friend told her that she has 33 that
Kryger [21]
320/80 = 4
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4 years ago
Plz help question below
ad-work [718]
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3 years ago
What is the antiderivative of sin^2(x)cos^2(x)?
marin [14]

Answer:

\frac{x}{8}-\frac{\sin(4x)}{32}+C

Step-by-step explanation:

[Most of the work here comes from manipulating the trig to make the term (integrand) integrable.]

Recall that we can express the squared trig functions in terms of cos(2x). That is,

\cos(2x)=2\cos^2x-1 \\ \cos(2x)=1 - 2\sin^2x.

And so inverting these,

\cos^2x=\frac{1}{2} (1+\cos2x) \\ \sin^2x=\frac{1}{2} (1-\cos2x).

Multiply them together to obtain an equivalent expression for sin^2(x)cos^2(x) in terms of cos(2x).

\sin^2x \cdot \cos^2x =\frac{1}{2} (1-\cos2x) \cdot \frac{1}{2} (1+\cos2x) = \frac{1}{4}(1-\cos^2(2x)).

Notice we have cos^2(2x) in the integrand now. We've made it worse! Let's try plugging back in to the first identity for cos^2(2x).

\cos(2x)=2\cos^2x-1 \Rightarrow \cos(4x)=2\cos^2(2x)-1 \Rightarrow \cos^2(2x) = \frac{1}{2}(1+\cos(4x))

So then,

\sin^2x \cdot \cos^2x = \frac{1}{4}(1-\cos^2(2x)) = \frac{1}{4}(1-\frac{1}{2}(1+\cos(4x))) = \frac{1}{4}(1-\frac{1}{2}-\frac{1}{2}\cos(4x))=\frac{1}{8}(1-\cos(4x)).

This is now integrable (phew),

\int \sin^2x\cos^2x \ dx = \int \frac{1}{8}(1-\cos(4x)) \ dx = \frac{1}{8} \int (1-\cos(4x)) \ dx = \frac{1}{8}(x-\frac{1}{4}\sin(4x))+C.

7 0
3 years ago
A volume of a sphere is 792\7cm cube find its surface area
olga_2 [115]

Answer: The answer is 113.14 cm^{2}. The detailed answer is given below:

Step-by-step explanation:

volume of sphere = 4/3 \pi r^{3}                       ∴ where radius = r

                              =792/7

now, we find r.

4/3 \pi r^{3} = 792/7

⇒\pi r^{3} = 792/7 x 3/4                             ( bring 3/4 to RHS )

⇒r^{3} = 594/7 x 7/22                         ( bring \pi to RHS )

⇒r^{3} = 27

⇒r = \sqrt{27}

⇒r = 3                                                                                                        _(1)

surface area of sphere = 4\pi r^{2}

                                       = 4 x 22/7 x 3^{2}                    ( from _(1) )

                                       = 113.14 cm^{2}

4 0
3 years ago
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