Ask question

Ask question

All categories

3 years ago

5

Carol sold twice as many magazine subscriptions as Jennifer. If Carol and Jennifer sold 90 subscriptions in all, how many subscr

iptions did Carol sell?
45
90
30
60

1 answer:

goblinko [34]3 years ago

3 0

Hello there!

Carol would have sold 60 subscriptions and Jenifer would have sold 30

The correct answer is option D, 60

I hope this help!

You might be interested in

ON A BUS ROUTE, THREE NEW PEOPLE GET ON THE BUS AT EACH STOP AFTER THE FIRST ONE. AT THE FIRST STOP SEVEN PEOPLE GET ON THE BUS.

Mumz [18]

7,3...

since we don't know how many stops after there are we will assume it just continues on and put three dots. (...)

Please rate and thank if I helped and tag me if you need help again!

7 0

3 years ago

If we subtract 22 from three times of number we get 68 find the number

aleksandrvk [35]

Answer:

90,30

Step-by-step explanation:

let the three times be 3x then,

3x-22=68

3x=68+22

3x=90

x=90/3

x=30

again,

3x=3*30=90

please support me and give me brainliest

4 0

3 years ago

Which equation gives the number of 1/4 centimeter that are in 7/3 centimeter?

Deffense [45]

Answer:

7/8 divided by 1/4 = 7/2

Step-by-step explanation:

Use the reciprocal when dividing fractions. :)

3 0

2 years ago

How do I solve 1 1/2c = 6

quester [9]

$1 \frac{1}{2} c = 6 \\ \\ \frac{2 + 1}{2} c = 6 \ / \ convert \ to \ improper \ fraction \\ \\ \frac{3}{2} c = 6 \ / \ simplify \\ \\ \frac{3c}{2} = 6 \ / \ simplify \\ \\ 3c = 6 \times 2 \ / \ multiply \ each \ side \ by \ 2 \\ \\ 3c = 12 \ / \ simplify \\ \\ c = \frac{12}{3} \ / \ divide \ each \ side \ by \ 3 \\ \\ c = 4 \ / \ simplify \\ \\$

So, your answer to this problem is c = 4.

6 0

3 years ago

Read 2 more answers

25 POINTS AND BRAINLIEST PLEASE HELP ASAP

dexar [7]

M is a midpoint of BC so:

$M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)$

Length of MA:

$MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

Length of NB:

$NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

5 0

3 years ago

Read 2 more answers