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2 years ago

Find the value of x in the isosceles triangle shown below

Mathematics

2 answers:

olasank [31]2 years ago

7 0

X=10 you’ll have to break down your equation to solve the square root.

egoroff_w [7]2 years ago

6 0

Answer:

x = 10

Step-by-step explanation:

if there 2 same triangle then they are right triangle

By using Pythagorean theorem for 1 of right triangle, we have

$\sqrt{74} ^{2}$ = $7^{2}$ + $(\frac{x}{2}) ^{2}$

74 = 49 + $\frac{x^{2}}{4}$

74 - 49 = $\frac{x^{2}}{4}$

25 = $\frac{x^{2}}{4}$

therefore, x = $\sqrt{25*4}$ = $\sqrt{100}$ = 10

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Answer:

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Step-by-step explanation:

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2 years ago

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The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?

VARVARA [1.3K]

Answer:

$\displaystyle - 155$

Step-by-step explanation:

we are given a quadratic function

$\displaystyle f(x) = - 5 {x}^{2} + 30x - 200$

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

$\displaystyle x _{ \rm min} = \frac{ - b}{2a}$

the given function is in the standard form i.e

$\displaystyle f(x) = a {x}^{2} + bx + c$

so we acquire:

b=30
a=-5

thus substitute:

$\displaystyle x _{ \rm min} = \frac{ - 30}{2. - 5}$

simplify multiplication:

$\displaystyle x _{ \rm min} = \frac{ - 30}{ - 10}$

simply division:

$\displaystyle x _{ \rm min} = 3$

plug in the value of minimum x to the given function:

$\displaystyle f (3)= - 5 {(3)}^{2} + 30.3 - 200$

simplify square:

$\displaystyle f (3)= - 5 {(9)}^{} + 30.3 - 200$

simplify multiplication:

$\displaystyle f (3)= - 45 + 90- 200$

simplify:

$\displaystyle f (3)= - 155$

hence,

the minimum value of the function is -155

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2 years ago