In the figure above, you are given the value of a start equal to 10 and the clover equal to 5. You are given a pole with three strings divided equally, the center string is tied to a wall and the two other strings carry either of the items. The first string has two stars and one clover which will have a total of 25 and the other string has one star and three clovers which will have a total of 25. The name of this type of problem is addition. Overall, the total weight of the items is 50.
Both the equations are the same so there is no point of intersection then the equation has no solution.
The system of equations that has no solution is, the correct option is A.
![\rm 5 x + 5 y = 10 \\\\2 x + 2 y = 4](https://tex.z-dn.net/?f=%5Crm%205%20x%20%2B%205%20y%20%3D%2010%20%5C%5C%5C%5C2%20x%20%2B%202%20y%20%3D%204)
What have to determine
Which system of equations has no solution?
<h3>What is a system of equations?</h3>
A system of linear equations is a collection of two or more linear equations.
The set of equations "which cannot be solved for x and y values is said to have no solution".
The system of equations has no solution is;
![\rm 5 x + 5 y = 10 \\\\2 x + 2 y = 4](https://tex.z-dn.net/?f=%5Crm%205%20x%20%2B%205%20y%20%3D%2010%20%5C%5C%5C%5C2%20x%20%2B%202%20y%20%3D%204)
Divided by 5 equation 1
![\rm 5x+5y=10\\\\x+y=2](https://tex.z-dn.net/?f=%5Crm%205x%2B5y%3D10%5C%5C%5C%5Cx%2By%3D2)
Divided by 2 equation 2
![\rm 2x+2y=4\\\\x+y=2](https://tex.z-dn.net/?f=%5Crm%202x%2B2y%3D4%5C%5C%5C%5Cx%2By%3D2)
Hence, both the equation are the same so there is no point of intersection then the equation has no solution.
To know more about the system of equations click the link given below.
brainly.com/question/12895249
Here is the answer for your problem. You will first need to divide by negative four to isolate the Y as it’s own variable. Then, there is the problem of that 3/4x on your left side. By subtracting it from both sides, you are isolating your Y all by itself and solving for Y.
Answer:
The answer is √5 .
Step-by-step explanation:
You have to rationalize the fraction in order to get rid of surd in the denorminator by multiplying √3 to both numerator amd denorminator :
![\frac{ \sqrt{15} }{ \sqrt{3} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B15%7D%20%7D%7B%20%5Csqrt%7B3%7D%20%7D%20)
![= \frac{ \sqrt{15} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B15%7D%20%7D%7B%20%5Csqrt%7B3%7D%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20%7D%7B%20%5Csqrt%7B3%7D%20%7D%20)
![= \frac{ \sqrt{15} \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B15%7D%20%5Ctimes%20%20%5Csqrt%7B3%7D%20%20%7D%7B%20%5Csqrt%7B3%7D%20%20%5Ctimes%20%20%5Csqrt%7B3%7D%20%7D%20)
![= \frac{ \sqrt{45} }{3}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B45%7D%20%7D%7B3%7D%20)
![= \frac{ \sqrt{9 \times 5} }{3}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B9%20%5Ctimes%205%7D%20%7D%7B3%7D%20)
![= \frac{3 \sqrt{5} }{3}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B3%20%5Csqrt%7B5%7D%20%7D%7B3%7D%20)
![= \sqrt{5}](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B5%7D%20)