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2 years ago

What is 2x-y <4 graphed on a graph

Mathematics

1 answer:

photoshop1234 [79]2 years ago

7 0

Answer:

y>2x-4

y int = -4

over 2 right 1 (like staircase)

The line is dotted and shade to the left of graph

Step-by-step explanation:

You might be interested in

Y=6x+5 is the equation. what is its gradient

Irina18 [472]

Gradient is synonymous to slope.

y = 6x + 5 is an example of a slope-intercept form of a straight-line equationl.

The slope-intercept equation is like this:

y = mx + b

where : m = slope ; b = "y-intercept"

y = 6x + 5

6 is the slope
5 is the y-intercept.

Since slope and gradient are synonymous, 6 is the gradient of the above equation.

8 0

3 years ago

Amanda has $75 in her savings accountwhile Julie has $30 in her savings account Amanda adds $5 per week into her allowance and J

ELEN [110]

Answer:

$100

Step-by-step explanation:

Every week Amanda adds $5 and every week Julia adds $14. So all you have ti do is add $5 to Amanda's account and $14 to Julia's account until you have the same amount of money for the both of them.

5 0

3 years ago

The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo

oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY = $\sqrt{x^2+y^2}$

Therefore, the length between points AB is

length AB = $\sqrt{(-4 - (-2))^2+(-1-3)^2}$

= $\sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2} = \sqrt{20}$ = 4.472 units

Similarly, length BC is given by

Length BC = $\sqrt{(-4)^2+1^2} = \sqrt{17}$ = 4.123 units

Length CD = $\sqrt{(-2)^2+5^2} = \sqrt{29}$ = 5.385 units

Length DA = $\sqrt{(8)^2+(-2)^2} = \sqrt{68}$ = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A = $\sqrt{(7)^2+(0)^2} = \sqrt{49}$ =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

$S_{\bigtriangleup}$ = $(\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|$

= $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

$S_{{\bigtriangleup}ABC}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|$

= $=(\frac{1}{2})|-4-6 -8|= 9 units^2$

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

$S_{{\bigtriangleup}ACD'}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2}$ = 10.5 units²

Area of polygon = $S_{{\bigtriangleup}ABCD'}$ = $S_{{\bigtriangleup}ABC}$ + $S_{{\bigtriangleup}ACD'}$ = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0

3 years ago

The sum of two numbers is 39, One number is 7 more than the other. Find the two numbers.

vfiekz [6]

The answer is.. 23 and 16

Hope this helps!!

5 0

3 years ago

(7x10*5)x(3x10*2) in standerd form

marishachu [46]

Answer:

21,000

Step-by-step explanation:

This is more of straightforward multiplication, so I cannot explain much! If you want me to try to do more, then just comment.

(7 * 10 * 5) * (3 * 10 * 2)

= (70 * 5) * (30 * 2)

= (350) * (60)

= 21,000

Thusly, in standard form, the equation given is $\boxed{21,000}$ .

Hope this helps! (:

7 0

3 years ago