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4 years ago

13

The graph of f(x)=x^6-2x^4-5x^2+6

1 answer:

dimulka [17.4K]4 years ago

8 0

It is this but it keeps going up.

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Jenna receives a job offer to work as a personal assistant. She is told she will receive $12 an hour, health insurance, overtime

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Paid vacation and health insurance

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3 years ago

The _____ a0 of a segment divides the segment into two segments of equal length.

Alexeev081 [22]

The <u>Midpoint</u> of a segment divides the segment into two segments of equal length.

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3 years ago

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Which statement about the solution of the inequality k<-3 1/4 is true?

Juliette [100K]

Answer: Last option

The number -8.4 is a solution to the inequality because -8.4 is located to the left of $-3\frac{1}{4}$ on the number line.

Step-by-step explanation:

Note that: $-3\frac{1}{4} =-3-\frac{1}{4} =-3.25$

The inequality is:

$k$

The inequality is:

This means that the inequality includes all values of the number line that are less than -3.25 or that are to the left of -3.25

__-8.4_________-3.25_-3____0___0.9____________7.1__

Note that the number -8.4 is less than -3.25, because it is to its left on the number line.

Then the correct statement is:

The number -8.4 is a solution to the inequality because -8.4 is located to the left of $-3\frac{1}{4}$ on the number line.

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3 years ago

Read 2 more answers

Nuetrik [128]

Answer:

Step-by-step explanation:

3x^2 - 5x + 12 - (5x^2 + x - 11) =

3x^2 - 5x + 12 - 5x^2 - x + 11 =

-2x^2 - 6x + 23 <====

4 0

3 years ago

Verify a÷(b+c)not equal(a÷b)+a÷c for each of the following values of a, b and c

just olya [345]

Answer:

a) and b) satisfied the condition of the given equation.

Step-by-step explanation:

Given: $\frac{a}{(b + c)}$ ≠ $\frac{a}{b}$ + $\frac{a}{c}$

Then,

$\frac{a}{(b + c)}$ ≠ $\frac{(ac + ab)}{bc}$

a) For a = 21, b = 4 and c = -2, then we have;

$\frac{21}{(4 + (-2))}$ ≠ $\frac{(21*-2 + 21*4)}{4*-2}$

$\frac{21}{4 - 2}$ ≠ $\frac{(-42 + 84)}{-8}$

$\frac{21}{2}$ ≠ $\frac{42}{-8}$

$\frac{21}{2}$ ≠ $-\frac{21}{4}$

Therefore the condition of the given equation is satisfied.

b) For a = 1, b = 10 and c = 1, then we have:

$\frac{1}{(10 + 1)}$ ≠ $\frac{(1*1 + 1*10)}{10*1}$

$\frac{1}{11}$ ≠ $\frac{(1 + 10)}{10}$

$\frac{1}{11}$ ≠ $\frac{11}{10}$

Therefore the condition of the given equation is satisfied.

5 0

3 years ago