The answer is expressions D, E, and G.
In algebra, a ‘term’ usually means the different parts of an expression that are separated by + and - signs.
Options A and B only have 1 term, an x or y³, so these are incorrect.
Option C has 1 term as well, ‘xyz’, because they are all multiplied together which makes it one term.
D and E both have 3 terms each, but F has 4 unique terms so this is incorrect also.
G has 3 unique terms, x³, x^4, and 7x, so this is correct.
When H is expanded, you will end up with more than 3 unique terms, so this is incorrect.
I hope this helps!
C = 12.2
Not sure if it’s the pythagorean theorem..
A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.
C) The probability the golfer got six holes-in-one during a single game is close to 0%.
<h2 /><h2><u>How to determine probabilities</u></h2>
Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:
- 1 - 0.12 = 0.88
- 0.88 ^ 17 = 0.1138
- 0.88 ^ 18 = 0.1001
Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
- 0.88 ^ 18 - 0.12 ^ 2 = X
- 0.0857 = X
Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.
- 0.12 ^ 6 x 0.88 ^ 12 = X
- 0.0000000001 = X
Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.
Learn more about probabilities in brainly.com/question/25273534
Answer:
(5/2,0) and(-4,0)
Step-by-step explanation:
I hope this helps.
