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Tanya [424]
2 years ago
9

tania brings 8.32 to the candy store. she wants to buy 21 jawbreakers does she have enough money? round your answer down to the

nearest whole number
Mathematics
1 answer:
Neporo4naja [7]2 years ago
3 0

Based on the information given regarding the equation, it can be noted that Tania doesn't have enough money.

<h3>How to solve an equation</h3>

Your information is incomplete. Therefore, an overview will be given. Let's assume that the price of a jawbreaker is 0.45.

Therefore, the cost of 21 jawbreakers will be:

= 21 × 0.45

= 9.45

In this case, the person has 8.32. Therefore, it can be noted that she doesn't have enough money.

Learn more about equations on:

brainly.com/question/13763238

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Simplify 4 + 10 ÷ (–2).
Gnesinka [82]

Answer:

-1 Your answer is A

Step-by-step explanation:

4+ 10/-2=-1

10/-2=-5

4+-5=-1

3 0
3 years ago
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Which expression would be easier to simplify if you used the commutative property to change the order of the numbers?
In-s [12.5K]

Answer:

the 3rd one

Step-by-step explanation:

20+17=37

-1/2+(-5/2)= -3

so 37 + ( -3 ) = -3 + 37 have the same value which is 34

3 0
2 years ago
A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.
stich3 [128]

Answer:

The distance between 12m-sides is 5\sqrt{2}m.

Step-by-step explanation:

It is given that the parallelogram has sides 10m and 12m and an angle of 45°.

Draw an altitude from one 12m side to another 12 m side as shown in below figure.

The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.

Since angle C is acute angle therefore it must be 45 degree.

\sin\theta=\frac{perpendicular}{hypotenuse}

\sin C=\frac{BE}{BC}

\sin(45^{\circ})=\frac{d}{10}

\frac{1}{\sqrt{2}}=\frac{d}{10}

\frac{10}{\sqrt{2}}=d

\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=d

\frac{10\sqrt{2}}{2}=d

5\sqrt{2}=d

Therefore the distance between 12m-sides is 5\sqrt{2}m.

4 0
3 years ago
Is y=-3/4x + 8 linear?
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Answer:

Yes

Step-by-step explanation:

8 0
3 years ago
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. Among all the income tax forms filed in a certain year, the mean tax paid was $2000, and the standard deviation was $500. In a
Anarel [89]

Answer:

a) 0.8413

b) 0.6293

Step-by-step explanation:

Data provided:

Mean tax paid = $2000

Standard deviation = $500

Sample size, n = 625

n=625

Now,

a) P( average tax paid on the sample forms is greater than $1980)

⇒ P(X > 1980)

or

⇒ P(\frac{(X-mean)}{\frac{s}{\sqrt n}})

or

⇒ P(\frac{(1980-2000)}{\frac{500}{\sqrt{625}}})

or

⇒ P(Z > -1)

or

= 0.8413 (From standard normal table)

b) P(more than 60 of the sampled forms have a tax of greater than $3000)

given:  p = 10% = 0.1

Now, by using CLT

mean = n × p

= 625 × 0.1

= 62.5

Standard deviation, s =\sqrt{n\times p\times(1-p)}

=\sqrt{625\times0.1\times(1-0.1)}

= 7.5

Thus,

P(X > 60)

= P(\frac{(X-mean)}{s} > \frac{(60-62.5)}{7.5})

or

= P(Z > -0.33)

= 0.6293     (From standard normal table)

4 0
3 years ago
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