tania brings 8.32 to the candy store. she wants to buy 21 jawbreakers does she have enough money? round your answer down to the
1 answer:
You might be interested in
First bag has 47 coins and second bag has 49 coins and third bag has 51 coins and fourth bag has 53 coins
<em><u>Solution:</u></em>
Given that,
Total number of coins = 200
Number of bags = 4
<em><u>I put the coins into each bag so that each bag has 2 more coins than the one before</u></em>
Therefore,
Each bag has 2 more coins than the one before. Based on this we can say,
Let "x" be the number of coins put in first bag
Then, x + 2 is the number of coins put in second bag
Then, x + 4 is the number of coins put in third bag
Then, x + 6 is the number of coins put in fourth bag
We know that,
Total number of coins = 200
Thus,
Coins put in first bag = x = 47
Coins put in second bag = x + 2 = 47 + 2 = 49
Coins put in third bag = x + 4 = 47 + 4 = 51
Coins put in fourth bag = x + 6 = 47 + 6 = 53
Thus number of coins in each bag are found