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3 years ago

ANSWER THIS QUICKLY PLEASE!!!!!!!!!

Mathematics

2 answers:

Vika [28.1K]3 years ago

8 0

It's the second answer.

Tems11 [23]3 years ago

5 0

C. 2 sq rt 2 + sq rt 5 + sq rt5 + sq rt 2

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I=\sqrt{-1}i= −1 i, equals, square root of, minus, 1, end square root, what is the sum (7+3i)+(-8+9i)(7+3i)+(−8+9i)left parent

nata0808 [166]

We can simply add the expression to simplify the expression. So,

(7+3i)+(-8+9i) =7 +3i -8+9i Get rid of paranthesis.

=(7-8)+(3i+9i) Group the like terms.

= -1 + 12i

4 0

3 years ago

0.038 x 10 with a power of negative 2

Ghella [55]

The correct answer will be 0.00038

The easiest way to solve is if the exponent is positive you move the decimal to the right and if the exponent is negative the decimal moves to the left.

3 0

3 years ago

What is the solution to the system of equations below?

Andre45 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equations

$y=-6x-10$

$y=-3x-21$

solving the system of the equations

Arrange the equation variables for elimination

$\begin{bmatrix}y+6x=-10\\ y+3x=-21\end{bmatrix}$

$y+3x=-21$

$-$

$\underline{y+6x=-10}$

$-3x=-11$

$\begin{bmatrix}y+6x=-10\\ -3x=-11\end{bmatrix}$

solve

$-3x=-11$

Divide both sides by -3

$\frac{-3x}{-3}=\frac{-11}{-3}$

$x=\frac{11}{3}$

$\mathrm{For\:}y+6x=-10\mathrm{\:plug\:in\:}x=\frac{11}{3}$

$y+6\cdot \frac{11}{3}=-10$

$y=-32$

Therefore, the solutions to the system of the equations are:

$y=-32,\:x=\frac{11}{3}$

But, it seems none of the options is true.

8 0

3 years ago

Read 2 more answers

Someone please help.

UkoKoshka [18]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Factorisation.

Since here both are the roots of the quadratic equation in the factor form, hence

equate them to zero, to get the value of x

hence,

2x-9 = 0

===> x = 9/2

and

3x+5=0

===> x = -5/3

6 0

2 years ago

Read 2 more answers

Which expressions are equivalent to the given sort 40 (there is more than one and the one selected is correct)

Basile [38]

Answer:

$40 {}^{ \frac{1}{2} }$

Step-by-step explanation:

The last one is also the answer

Using the rational exponet rule,

$\sqrt[n]{ {x}^{m} } = x {}^{ \frac{m}{n} }$

Using this number,

$\sqrt{40}$

40 is the base so it will stay same. Remember this is a square root sign so our nth root is 2 so our denominator if the rational exponet is 2.

$40 {}^{1} = 40$

so our numerator is 1 so

$40 {}^{ \frac{1}{2} }$

3 0

3 years ago