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bearhunter [10]
3 years ago
7

Draw an angle measuring 700 degrees in standard position.

Mathematics
1 answer:
3241004551 [841]3 years ago
7 0
A screenshot of the angle is attached.

700 is almost 2 complete revolutions around the graph.  700-360=340; this means it is the same as going 20° backwards from the starting point.

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1. what is the equation of a line that has an x-intercept of 2 and a y-intercept of 8
Phoenix [80]

Answer:

B

Step-by-step explanation:

x- intercept = 2  .So, Coordinate(2 , 0)

y-intercept = 8 . So, Coordinate (0, 8)

Slope = \frac{8-0}{0-2}\\\\=\frac{8}{-2}\\\\=-4

Slope y-intercept form: y = mx + b  {Here, b is y-intercept}

y = -4x + 8

8 0
2 years ago
I rly need some help please
kicyunya [14]

Answer:

B) 12.5%

Step-by-step explanation:

1. Find amount spent on clothes in July

$2800 * 8% = j

<em>j = $224</em>

2. Find amount spent of clothes in August

$224 + $126 = a

<em>a = $350</em>

3. Find the amount's percentage of the total

$350/$2800 = x

x = 0.125 = 12.5%

6 0
3 years ago
Plz help me out with this one. :(
Anettt [7]
I think it is C)
I’m really sorry if I’m wrong.
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5
DanielleElmas [232]

Answer:

1

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that csc(x)=1/sin(x) and sec(x)=1/cos(x).

Thus:

\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}

=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }

Let's do the first part first: (Recall how to divide fractions)

\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}

For the second term:

\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}

So, all together: (same denominator; combine terms)

\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}

Note the numerator; it can be derived from the Pythagorean Identity:

sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)

Thus, we can substitute the numerator:

\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1

Everything simplifies to 1.

7 0
2 years ago
The relation ((6, 8), (7, 10), (7, 12), (8, 16),
Brilliant_brown [7]

Answer:

x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

Step-by-step explanation:

Given the relation

  • {(6, 8), (7, 10), (7, 12), (8, 16), (10, 16)}

We know that a relation is a function that has only one output for any unique input.

As the inputs or x-values of the relations are:

at x = 6, y = 8

at x = 7, y = 10

at x = 7, y = 12

at x = 8, y = 16

at x = 10, y = 16

If we closely observe, we can check that there is a repetition of x values.

i.e. x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

8 0
3 years ago
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