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lana66690 [7]
2 years ago
12

Frank works as a waiter and as a busser. He earns $12 per hour as a waiter and $10 per hour as a busser. Last week, Frank worked

both jobs for a total of 36 hours, and earned a total of $410. How long did Frank work as a waiter last week?
Mathematics
1 answer:
DedPeter [7]2 years ago
8 0

Frank worked 25 hours as a waiter last week.

<h2>Simultaneous equation</h2>
  • Let the time spent as a waiter be x
  • Leet the total time spent as a busser be y

If<u> Frank worked both jobs f</u>or a total of 36 hours, hence:

x + y = 36

x = 36 - y

Also, if he earns $12 per hour as a waiter and $10 per hour as a busser and earned a total of $410, then;

12x + 10y = 410

Substitute 1 into 2

12x + 10y = 410

12(36 - y)+ 10y = 410

432 -12y + 10y = 410

-2y = -22

y = 11

Since x = 36 - y

x = 36 - 11

x = 25

Hence frank worked 25 hours as a waiter last week.

Learn more in simultaneous equation here: brainly.com/question/16863577

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The equation 2x^2 + x - 1 = 0 has two solutions. Find an equation of the form ax^2 + bx + c = 0, which solutions....
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Step-by-step explanation:

Let the solution to

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are a and b

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ab = -1/2 (the constant)

A. We want to have an equation where the roots are a +5 and b+5.

Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.

The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.

So the equation is

x^2-(19/2)x + 22 =0

2x^2-19x + 44 =0

B. We want the roots to be 3a and 3b.

Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and

(3a)(3b) = 9(ab) =9(-1/2)=-9/2.

So the equation is

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4 0
3 years ago
Modern car company has come out with a new car model. Market analysts predict that 4,600 cars will be sold in the first month an
Arte-miy333 [17]

The first five terms of the sequence are; 4,600, 4,550, 4,500, 4,450, 4,400 and the total predicted number of sold cars for the first year is 51,900 cars

<h3>Arithmetic sequence</h3>

  • First month, a = 4,600 cars
  • Common difference, d = -50 cars

First five terms;

a = 4,600

a + d = 4600 + (-50)

= 4600 - 50

= 4,550

a + 2d

= 4600 + 2(-50)

= 4600 - 100

= 4,500

a + 3d

= 4,600 + 3(-50)

= 4,600 - 150

= 4,450

a + 4d

= 4600 + 4(-50)

= 4,600 - 200

= 4,400

cars predicted for the twelfth month.

a + 11d

= 4600 + 11(-50)

= 4600 + 550

= 4,050

Total predicted number of sold cars for the first year:

Sn = n/2{2a + (n - 1)d }

= 12/2{2×4600 + (12-1)-50}

= 6{9200 + 11(-50)}

= 6(9,200 - 550)

= 6(8,650)

= 51,900 cars

Learn more about arithmetic sequence:

brainly.com/question/6561461

#SPJ1

7 0
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