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lana66690 [7]
2 years ago
12

Frank works as a waiter and as a busser. He earns $12 per hour as a waiter and $10 per hour as a busser. Last week, Frank worked

both jobs for a total of 36 hours, and earned a total of $410. How long did Frank work as a waiter last week?
Mathematics
1 answer:
DedPeter [7]2 years ago
8 0

Frank worked 25 hours as a waiter last week.

<h2>Simultaneous equation</h2>
  • Let the time spent as a waiter be x
  • Leet the total time spent as a busser be y

If<u> Frank worked both jobs f</u>or a total of 36 hours, hence:

x + y = 36

x = 36 - y

Also, if he earns $12 per hour as a waiter and $10 per hour as a busser and earned a total of $410, then;

12x + 10y = 410

Substitute 1 into 2

12x + 10y = 410

12(36 - y)+ 10y = 410

432 -12y + 10y = 410

-2y = -22

y = 11

Since x = 36 - y

x = 36 - 11

x = 25

Hence frank worked 25 hours as a waiter last week.

Learn more in simultaneous equation here: brainly.com/question/16863577

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Answer:

0.66

Step-by-step explanation:

GIVEN: Suppose that in a certain county 37\% of voters are registered as Democrats, 29\% as Republicans, 7\% as Green party, and the rest are considered Independents. You conduct a poll by calling registered voters in the county at random.

TO FIND: Probability that the first call will be to either a Democrat or a Republican.

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Lets total population of county be 100x.

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voters registered as Republicans =29\%=\frac{29}{100}\times100x

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Probability that first call will be to Democrats P(A)=\frac{\text{total democrats}}{\text{total voters}}

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Probability that first call will be to Republican P(B)=\frac{\text{total republicans}}{\text{total voters}}

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probability that the first call will be to either a Democrat or a Republican

=P(A)+P(B)

=0.37+0.29

=0.66

Hence the probability that the first call will be to either a Democrat or a Republican is 0.66

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