9514 1404 393
Answer:
p(1) = 6
Step-by-step explanation:
The basic idea is to put 1 wherever you see x. That gives you ...
p(1) = 2·1² +3·1 +1
The powers of x are all 1 when x=1, so the value of p(1) is just the sum of the coefficients:
p(1) = 2 + 3 + 1
p(1) = 6
Answer:
Step-by-step explanation:
![\displaystyle \frac{3\sqrt{3}}{2}a^2 = A \hookrightarrow \frac{3\sqrt{3}}{2}6^2 = A \\ \frac{3\sqrt{3}}{2}[36] = A; 54\sqrt{3}\:[or\:93,530743609...] \\ \\ \boxed{93,5 \approx A}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7Da%5E2%20%3D%20A%20%5Chookrightarrow%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7D6%5E2%20%3D%20A%20%5C%5C%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7D%5B36%5D%20%3D%20A%3B%2054%5Csqrt%7B3%7D%5C%3A%5Bor%5C%3A93%2C530743609...%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7B93%2C5%20%5Capprox%20A%7D)
I am joyous to assist you at any time.
Set it up as 15x-13+8x+29+2y=180 and then just find a algebra calculator and put that formula in there
27, 140 is the correct answer
Answer:
5
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Step-by-step explanation:
