Remark
I take it MO is bisected by N. If it isn't we need some clue how to proceed.
Step One
Solve for x
9x = 2(x + 7) remove the brackets.
9x = 2x + 14 Subtract 2x from both sides.
9x - 2x = 14
7x = 14 Divide by 7
x = 14/7
x = 2
Step Two
Find MO
2(x + 7) + 9x = MO
2(2 + 7) + 9(2) = MO
2*9 + 9*2 = MO
18 + 18 = MO
36 = MO <<<<< Answer
Answer:
17 coaches
Step-by-step explanation:
820 divided by 50 is 16.4 but you can't have part of a coach so you round up it 17
Answer:
The new width is 3 in.
Step-by-step explanation:
We can use the ratio of w/h, the origal width and height should have the same ratio as the new width and height.
<u>12 </u>= <u>x</u>
16 4
Then solve for x:
x = 4 (12/16)
x = 3
To check:
12/16 = 3/4
3/4 = 3/4
1 over the square root of 8 = 4(m - 2) equals m = 2 + the square root of 2<span>2/2 or approximately 2.71. To solve this you need to find the variable, isolate the variable, and then solve. Remember that whatever happens to one side of the equation has to happen to the other.</span>
We need to assign a value for x to check the possible values of y.
1st inequality: y < -0.75x
X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT
X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN
X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT
2nd inequality: y < 3x -2
X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT
X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT
X = 1 ; y < 3(1) – 2 ; y <<span> 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT
The actual solution to the system lies on the 4TH QUADRANT.
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