If the population is doubling every 10 years, the rate of change is 100%, for the period of 10 years, so, whatever it happens to be at the time, it grows by 100%, namely it doubles.
![\bf \textit{Periodic Exponential Growth}\\\\ A=I(1 + r)^{\frac{t}{p}}\qquad \begin{cases} A=\textit{accumulated amount}\\ I=\textit{initial amount}\to &4100\\ r=rate\to 100\%\to \frac{100}{100}\to &1.00\\ t=\textit{elapsed time}\to &8\\ p=period\to &10 \end{cases} \\\\\\ A=4100(1 + 1)^{\frac{8}{10}}\implies A=4100(2)^{\frac{4}{5}}\implies A=4100\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7BPeriodic%20Exponential%20Growth%7D%5C%5C%5C%5C%0AA%3DI%281%20%2B%20r%29%5E%7B%5Cfrac%7Bt%7D%7Bp%7D%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AI%3D%5Ctextit%7Binitial%20amount%7D%5Cto%20%264100%5C%5C%0Ar%3Drate%5Cto%20100%5C%25%5Cto%20%5Cfrac%7B100%7D%7B100%7D%5Cto%20%261.00%5C%5C%0At%3D%5Ctextit%7Belapsed%20time%7D%5Cto%20%268%5C%5C%0Ap%3Dperiod%5Cto%20%2610%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D4100%281%20%2B%201%29%5E%7B%5Cfrac%7B8%7D%7B10%7D%7D%5Cimplies%20A%3D4100%282%29%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%5Cimplies%20A%3D4100%5Csqrt%5B5%5D%7B2%5E4%7D)
3.43 dollars divided by 7 minutes = 0.49 cents
<h3>Answers:</h3>
- Part A) Solution is (-3,-3)
- Part B) Two solutions are (0,0) and (2,2)
- Part C) Solution is x = -6
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Explanation:
Part A
Ignore the g(x) curve. We're looking for the intersection of the p(x) and f(x) curves. The two cross at (-3,-3) which is the solution to the system of these two equations. This point is on both p(x) and f(x) simultaneously. That means the coordinates of the point satisfy both p(x) and f(x) equations simultaneously.
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Part B
Pick any two points you want from the f(x) curve. You could pick the solution we mentioned, but I'll go for (0,0) and (2,2). When talking about a single curve, it has infinitely many solutions (as long as you pick a point on the curve).
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Part C
Ignore the f(x) curve. The graphs of p(x) and g(x) intersect when x = -6, which is the solution to the equation p(x) = g(x). We're only concerned about the x coordinate of the intersection.
