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Alik [6]
3 years ago
13

Find the surface area and volume OF THIS QUESTION TOO (question 99)

Mathematics
1 answer:
Svetllana [295]3 years ago
7 0

Answer:

439.6 cm²

Step-by-step explanation:

Surface area of the cylinder is the length of the rectangular strip that goes around, and the are of the two circles

Area circle = πr²

Area circle = 3.14 * 7²

Area circle = 3.14 * 49

Area circle = 153.86

The area of both circles is 153.86 x 2 = 307.72

The rectangular strip is the diameter by the height

Diameter = 2πr

Diameter = 14*3.14 = 43.96

The strip is 43.96 x 3 = 131.88

Total surface area is 307.72 + 131.88 = 439.6

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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2x - y/2
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The result is -8, so the pair (3,28) is a solution

3 0
3 years ago
Find the distance between the points (1,3) and (5,0).
Irina18 [472]

distance between two points is [(x2-x1)^2 +(y2-y1)^2]^1/2

I.e,[{5-1)^2+(0-3)^2]^1/2

[16+9]^1/2

[25]^1/2

5

5 0
3 years ago
Common numbers for 15 18 and 12
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8 0
3 years ago
the maximum walking speed S, in feet per second of an animal can be modeled by the equation S=the square root gL where g=32ft/se
swat32

The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

<h3>Calculating Maximum speed</h3>

From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus

From the give information,

The maximum walking speed, S, is given by

S = √gL

Where g = 32ft/sec
and L is the length of the animal's leg

Thus,

For a Giraffe with a leg length of 6 feet

S = √32×6

S = √192

S = 13.856 ft/sec

For a Hippopotamus with a leg length of 3 feet

S = √32×3

S = √96

S = 9.798 ft/sec

Now, we will determine how many times greater 13.856 is than 9.798

13.856/9.798 = 1.41

Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

Learn more on Calculating Speed here: brainly.com/question/15784810

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3 0
2 years ago
you are given an 8-gallon jug filled with water and also two empty jugs: one that holds 5 gallons and other that holds 3 gallons
Yanka [14]

Answer:

Step-by-step explanation:

We will use following steps to measure exactly 4 gallons of water with the help of 5 gallons and 3 gallons empty jugs.

1). Fill 3 gallons jug completely.

2). Pour this 3 gallons of water into 5 gallons jug. Now we have 3 gallons of water in 5 gallons jug and 3 gallons jug empty.

We can add 2 gallons of water in the empty space of 5 gallons jug more.

3). Fill the 3 gallons jug with the water again.

4). Pour this water into 5 gallons jug which can hold 2 gallons of water more.

Now we have 5 gallons of jug filled fully and 1 gallon water remaining in the 3 gallons jug.

5). Empty the 5 gallons jug completely.

6). Pour the remaining 1 gallon of remaining water in 3 gallons jug into 5 gallons jug.

7). Fill the 3 gallons jug completely and pour it into 5 gallon jug.

8). Finally we have 4 gallons of water in the 5 gallons jug.

8 0
3 years ago
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