This works just like exponential decay...
final=initial(rate^time)...
f=600(1-.29)^5
f(5)=108.25
The answer is the following: 800,000
The general formula for the margin of error would be:
z * √[p (1-p) ÷ n]
where:
z = values for selected confidence level
p = sample proportion
n = sample size
Since the confidence level is not given, we can only solve for the
<span>√[p (1-p) ÷ n] part.
</span>
p = 44/70
n = 70
√[44/70 (1 - (44/70) ÷ 70]
√[0.6286 (0.3714)] ÷ 70
√0.2335 ÷ 70
√0.0033357 = 0.05775 or 0.058 Choice B.
Answer:
<em><u>about 23 units</u></em>
Step-by-step explanation:
928,904+0
^
you could be lazy
