The given triangle has a right angle.
We use the mnemonics SOH-CAH-TOA.
1i)
,
,
ii)
,
,
,
,
2. We want to find the hypotenuse.
We know an angle to be 23 degrees.
We were also given the side opposite to this angle to be 1200km.
Therefore we use the sine ratio.
<u>c.)44 kilometers</u>
Answer:
Solution given:
let
length =L
and
Area =A
Now
we have
Area [A]=1936 square kilometers
now
As we know that
Area of square :length *length
A=l*l
A=l²
Substituting value of A
1936=l²
doing square root on both side

we get
l=
l=2*2*11
l=44 kilometers
So
<u>the length of one side of a </u><u>square</u><u> </u><u>is</u><u> </u><u>4</u><u>4</u><u> </u><u>kilometers</u><u>.</u><u />
Answer:
-sin(2A)
Step-by-step explanation:
1-(sin(A)+cons(A))^2
1-(sin(A)^2+2sin(A)cos(A)+cos(A)^2) :use FOIL to get it
1-(1+sin(2A))
1-1-sin(2A)
-sin(2A)
Answer:
144π
Step-by-step explanation:
we need the radisu
circumference formula: 2πr
2πr=24π
12=r
area formula:
πr²
12²π= 144π
Rhombus. The diagonals of a rhombus are parallel, and each diagonal bisect two angles of the rhombus.