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atroni [7]
2 years ago
9

The cost of Matt and Natalie's dinner was $27.35. They want to leave a 20% tip. Which of the following is the closest to the amo

unt of the tip they want to leave?
A. $4.00
B. $4.50
C. $5.00
D. $5.50
Mathematics
1 answer:
Ksenya-84 [330]2 years ago
8 0

Answer:

Option D is correct.

Step-by-step explanation:

27.35 x 20/100

=> 2.735 x 2/1

=> $5.47

=> $5.50 (Rounded)

Therefore, Option D is correct.

Hoped this helped.

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How many distinct arrangements can be formed from all the letters of "students"? Please show your work. Thanks!
topjm [15]

There are a total of 8 letters in student, with 6 different letters ( there are 2 s's and 2 t's).

First find the number of arrangements that can be made using 8 letters.

This is 8! which is:

8 x 7 x 6 x 5 x 4 3 x 2 x 1 = 40,320

Now there are 2 s's and 2 t's find the number of arrangements of those:

S = 2! = 2 x 1 = 2

T = 2! = 2 x 1 = 2

Now divide the total combinations by the product of the s and t's:

40,320 / (2*2)

= 40320 / 4

= 10,080

The answer is A. 10,080

6 0
3 years ago
Simplify this radical.
Zielflug [23.3K]

Answer:

3\sqrt{10}

Step-by-step explanation:

Assuming you mean \sqrt{90}

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab} , then

\sqrt{90}

= \sqrt{9(10)}

= \sqrt{9 × \sqrt{10}

= 3\sqrt{10}

6 0
3 years ago
Solve for x. <br><br> there’s a 76 and x.
Ghella [55]

Answer:

104

Step-by-step explanation:

The angle is supplementary, so the total angle measure (of 79 and x) is 180. Just subtract the value we have (76) from the total value (180), and you get x.

3 0
3 years ago
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
2 years ago
Which of the following proves these two triangles congruent by AAS?
Nataly [62]

Answer:

b is correct

Step-by-step explanation:

hope this helps

3 0
2 years ago
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