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Marrrta [24]
3 years ago
7

How to find slope in the equation 3x+5y=-5

Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

The slope is -3/5.

Step-by-step explanation:

3x+5y=-5

5y=-5-3x

5y=-3x-5

y=-3/5x-5/5

y=-3/5x-1

y=mx+b where m=slope and b=y-intercept

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Write an equation in slope-intercept form for the line that passes through (1, 1), and is perpendicular to the graph of 3x + 2y
defon

Answer:

2X-3Y = -1

Step-by-step explanation:

given equation is 3X +2Y = -7

FIRST BRING THIS IN SLOPE INTERCEPT FORM

2Y = -3X -7

DIVIDING EACH TERM BY 2

Y = (-3/2)X -7/2

SLOPE OF GIVEN EQUATION IS -3/2

SLOPE OF LINE PERPENDICULAR TO THIS IS NEGATIVE RECIPROCAL HENCE  SLOPE OF REQUIRED EQUATION IS 2/3

EQUATION OF STRAIGHT LINE IN POINT SLOPE FORM IS

Y-Y1 = m(X-X1)

Y-1 = (2/3)(X-1)

MULTIPLYING ALL TERMS BY 3

3(Y-1) = 2(X-1)

3Y-3 = 2X -2

2X-2 = 3Y-3

2X-3Y =-3+2

2X-3Y = -1

8 0
3 years ago
Read 2 more answers
A bricklayer is able to set 2.5 bricks in one minute. How many bricks can he set in 8 hours?
pochemuha

Given:

A bricklayer is able to set 2.5 bricks in one minute.

Required:

To find the number of bricks can he set in 8 hours.

Explanation:

8 hours =480 minutes.

2.5 bricks in one minute.

So for 480 minutes,

\begin{gathered} =2.5\times480 \\  \\ =1200 \end{gathered}

Final Answer:

1,200 bricks can he set in 8 hours.

5 0
1 year ago
Why the derivative of (x^2/a^2) = (2x/a^2)? ​
Neko [114]

I assume you're referring to a function,

f(x) = \dfrac{x^2}{a^2}

where <em>a</em> is some unknown constant. By definition of the derivative,

\displaystyle f'(x) = \lim_{h\to0}{f(x+h)-f(x)}h

Then

\displaystyle f'(x) = \lim_{h\to0}{\frac{(x+h)^2}{a^2}-\frac{x^2}{a^2}}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}{(x+h)^2-x^2}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}{(x^2+2xh+h^2)-x^2}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}{2xh+h^2}h \\\\ f'(x) = \frac1{a^2} \lim_{h\to0}(2x+h) = \boxed{\frac{2x}{a^2}}

8 0
3 years ago
HELP QUICK!
alexira [117]

Answer: y = 2x/3 - 5

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent.

The given line has a slope of 2/3 and it passes through (0,- 5)

To determine the intercept, we would substitute x = 0, y = - 5 and m= 2/3 into y = mx + c. It becomes

- 5 = 3/2 × 0 + c

c = - 5

The equation becomes

y = 2x/3 - 5

7 0
4 years ago
Center=(-2,3) and radius=4. Write the equation of the circle
lord [1]
Equation of a circle = (y-k)^2 + (x-h)^2 = r^2, where the center is at (h, k) and r = radius
{(y - 3)}^{2}  +  {(x + 2)}^{2} = 16
5 0
3 years ago
Read 2 more answers
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