Answer:
You want to solve for x, the first thing you need to do is distribute
The 2 through the x+4 then the other 2 through the -8-x
2(x+4)= 2x+8
2(-8-x)= -16-2x
2x+8=-16-2x-2x (combine like terms on the right side)
2x+8=-16-4x (now subtract 8 from each side)
2x=-24-4x (8-8=0, -16-8=-24) (now add 4x to each side)
6x=-24 (-4x+4x=0, 2x+4x=6x), (divide each side by 6)
x=-4 (6/6=1, -24/6=-4)
x=-4
Hope this helps ;)
3 x^3 y^2
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8 ( y/x-3/2)

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☆ Now Let's find value of sin A, cos A and tan A,
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- sin A = Perpendicular/Hypotenus =

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- cos A = Base/Hypotenus =

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- tan A = Perpendicular/Base =

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Answer:
(-1,3)
Step-by-step explanation:
so y=x+4 and y=-2x+1
obviously, y=y
so that means that x+4 is equal to -2x+1
let's use that
y=x+4,y=-2x+1
y=y
x+4=-2x+1
x+2x=1-4
3x=-3
x=-1
y=x+4
y=(-1)+4
y=3
(-1,3)
Answer:
Sorry what fraction
Step-by-step explanation:
ez matth