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marusya05 [52]
3 years ago
13

If f(x)=2x^2+1, what is f(x) when x =3 A)1B)7C)13D)19​

Mathematics
1 answer:
vlabodo [156]3 years ago
6 0

option D is right answer

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Ticketd to the school play cost $11 for adults and $6 for children. What expression can be used to find the toyal cost for x adu
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Answer:221

Step-by-step explanation:

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The Thompson family borrowed $120,000
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27,600

Step-by-step explanation:

6 0
3 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
Por favor alguien sabe cuál es. soy un número de 5 dígitos. Mi dígito de las decenas es la suma de mi cientos dígitos y miles de
mixas84 [53]

<span>47184. 
</span>
<span>Así que la suma de los cientos y miles será dos veces el dígito de las unidades . Miles ( 7 ) + cientos ( 1 ) = 8. 8 es dos veces más que el dígito de las unidades ( 4) de los miles de diez dígitos es el mismo que el de un dígito es así, esto hace que los miles a decenas 4 también .
</span>
(No escribo bien en espanol pero te lo traslatide jaja. dame un messaje si no todavia no entiendes) 
5 0
3 years ago
Which correctly compares (528 × 65) – 85 and (528 × 65) – 75 without doing any calculations?
OleMash [197]

Answer:

D.

Step-by-step explanation:

I don't actually know I'm guessing.

4 0
3 years ago
Read 2 more answers
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