3 years ago

G use part 1 of the fundamental theorem of calculus to find the derivative of the function. sqrt(4+7t)

Mathematics

1 answer:

uysha [10]3 years ago

6 0

Let y = √4+7t
then u= 4+7t
y=√u = u^½

du/dt= 7
dy/du = ½U^-½

dy/dt = du/dt • dy/du
= 7×½U^-½
= 7/2√U
= 7 / (2{√4+7t})

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