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zhannawk [14.2K]
4 years ago
15

NEGATIVE EXPONENTS - All of the following expressions are equal except _____.

Mathematics
1 answer:
worty [1.4K]4 years ago
5 0

The last one x^4.

A: If you bring 2^-5 to the numerator which is what the - expects you to do, then you get x^5 which is 32

B: No problem here. 32 = 32

C: 2^1 * 2^4 = 2^(1 + 4) = 2^5.

C: 2^5 is 32

D: 2^4 = 16.

Answer: D does not agree with the others.

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Simplify the expression below. 3x^2 - 5x^2 + 4x^2 <br><br> (Please explain how you get the answer)
Talja [164]

Answer:

The answer is -4x^2

Step-by-step explanation:

-3x^2 - 5x^2 + 4x^2

= -3x^2 + -5x^2 + 4x^2

Combine like terms:

-3x^2 + -5x^2 + 4x^2

(-3x^2 + -5x^2 + 4x^2)

= -4x^2

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Cada uno de los 28 estudiantes en la clase de Romi recaudó al menos $ 25 durante el jump-a-thon. ¿Cuál es la menor cantidad de d
Crank

Answer:

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Step-by-step explanation:


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How did British scientists test Einstein theory of relativity
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Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i
Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) \frac{20i+21}{29}

(c) i

Step-by-step explanation:

We have to perform division

(a) \frac{1-2i}{2i}

So after division

\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1

(b) We have given expression \frac{5-2i}{5+2i}

After rationalizing \frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}

(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i

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