the answer is in your question lol.
its pi, which is
≈ 3.14 feet ^3
^^^ thats
ur answer
710
Step-by-step explanation:
first you add 3 to 16 then 46 to 24 then 60 to 15 then 65 to 18 then 712 to 8
Answer:
299.99 miles
Step-by-step explanation:
Since the plane traveled due west,
The total angle is 49.17 + 90
Represent that with θ
θ = 49.17 + 90
θ = 139.17.
Represent the sides as
A = 170
B = 150
C = unknown
Since, θ is opposite side C, side C can be calculated using cosine formula as;
C² = A² + B² - 2ABCosθ
Substitute values for A, B and θ
C² = 150² + 170² - 2 * 150 * 170 * Cos 139.17
C² = 22500 + 28900 - 51000 * Cos 139.17
C² = 51400 - 51000 (−0.7567)
C² = 51400 + 38,591.7
C² = 89,991.7
Take Square Root of both sides
C = 299.9861663477167
C = 299.99 miles (Approximated)
Hence, the distance between the plane and the airport is 299.99 miles
Answer:
90
Step-by-step explanation:
Solution :
It is given that :
Casey boarded a Ferry wheel at position of 3 'o' clock.
The angular speed of the Ferry wheel = 5.6 radians per minute
The radius of the Ferry wheel = 50 feet
The height of the center wheel of the Ferry from the ground = 55 feet
Let the number of minutes be = t
a). The expression of the varying number of radians θ is given by :
After t minutes, θ = angle swept
θ = 5.6 t radians
b). Finding the height from the center of the wheel.
We know that : y = r sin θ
Given r = 50 feet
So, y = 50 sin (5.6 t) feet
Therefore, the height above the ground can be found by :
h = y + 55 (from ground)
h = 50 sin (5.6 t) + 55 feet
